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Which is the inverse of this matrix?

[tex]\[
\left[\begin{array}{ccc}
1 & 2 & 5 \\
3 & 6 & 9 \\
1 & 1 & -2
\end{array}\right]
\][/tex]

A. [tex]\(\left[\begin{array}{ccc}-19 & 9 & -7 \\ 15 & -7 & 6 \\ -2 & 1 & -1\end{array}\right]\)[/tex]

B. [tex]\(\left[\begin{array}{ccc}-19 & 9 & -7 \\ -2 & 1 & -1 \\ 15 & -7 & 6\end{array}\right]\)[/tex]

C. [tex]\(\left[\begin{array}{ccc}5 & -7 & 6 \\ -2 & 1 & -1\end{array}\right]\)[/tex]

D. [tex]\(\left[\begin{array}{cc}-19 & 9 \\ 15 & -7 \\ -2 & 1\end{array}\right]\)[/tex]

E. The matrix is noninvertible.


Sagot :

To determine the inverse of the given matrix
[tex]\[ \left[\begin{array}{ccc} 1 & 2 & 5 \\ 3 & 6 & 9 \\ 1 & 1 & -2 \end{array}\right] , \][/tex]
we assess its entries and calculate its inverse if it exists. Performing this calculation, we obtain the inverse matrix as:

[tex]\[ \left[\begin{array}{ccc} \frac{7}{2} & -\frac{3}{2} & 2 \\ -\frac{5}{2} & \frac{7}{6} & -1 \\ \frac{1}{2} & -\frac{1}{6} & 0 \end{array}\right] . \][/tex]

Let's compare this result with the given answer choices:

A. [tex]\(\left[\begin{array}{ccc}-19 & 9 & -7 \\ 15 & -7 & 6 \\ -2 & 1 & -1\end{array}\right]\)[/tex]

B. [tex]\(\left[\begin{array}{ccc}-19 & 9 & -7 \\ -2 & 1 & -1 \\ 15 & -7 & 6\end{array}\right]\)[/tex]

C. [tex]\(\left[\begin{array}{ccc}5 & -7 & 6 \\ -2 & 1 & -1\end{array}\right]\)[/tex]

D. [tex]\(\left[\begin{array}{cc}-19 & 9 \\ 15 & -7 \\ -2 & 1\end{array}\right]\)[/tex]

E. The matrix is noninvertible.

Our calculated inverse matrix does not match any of the given choices exactly as written in options A, B, C, or D. Furthermore, option E which suggests the matrix is noninvertible contradicts our result showing that it is indeed invertible.

Hence, the correct understanding is:
None of the provided options accurately represent the inverse of the matrix.