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Question 2 (Multiple Choice, Worth 5 points)

One's family will take a drive for [tex][tex]$1 \frac{1}{2}$[/tex][/tex] hours. They need to reach their destination by [tex]$1:15$ PM[/tex]. What is the latest time they can leave and still reach their destination on time?

A. 12:15 PM
B. 12:00 PM
C. 11:45 AM
D. [tex]$11:30$[/tex] AM


Sagot :

Let's break down the problem step-by-step to determine the latest time they can leave and still reach their destination by 1:15 PM, given that the drive will take 1 hour and 30 minutes.

### Step 1: Convert the drive time to minutes
The drive time is 1 hour and 30 minutes. To make calculations simpler, we'll convert this time entirely to minutes.
- 1 hour = 60 minutes
- 1 hour and 30 minutes = 60 minutes + 30 minutes = 90 minutes

### Step 2: Convert the destination time to minutes past midnight
The destination time is 1:15 PM. In a 24-hour format, 1:15 PM is:
- 1 PM = 13:00 hours
- 13:15 hours (1:15 PM) = 13 * 60 minutes + 15 minutes = 780 minutes + 15 minutes = 795 minutes

### Step 3: Calculate the latest leave time in minutes past midnight
To find the latest time to leave, we subtract the total drive time in minutes from the destination time in minutes.
- Destination time in minutes = 795 minutes
- Drive time in minutes = 90 minutes
- Latest leave time in minutes = 795 minutes - 90 minutes = 705 minutes

### Step 4: Convert the latest leave time back to hours and minutes
705 minutes need to be converted back into hours and minutes to make sense of it in clock time.
- 705 minutes / 60 = 11 hours and 45 minutes remaining

Thus, the latest time they can leave and still reach by 1:15 PM is 11:45 AM.

### Conclusion:

From the available options, the correct answer is:

11:45 AM