Let's break down the problem step-by-step to find the solution.
1. Initial Value:
The starting value is [tex]$\$[/tex]560[tex]$.
2. Percentage Reduction:
The value is reduced by 50%. To find the reduction, we calculate \(0.50 \times 560\).
\(0.50 \times 560 = 280\)
3. Reduced Value:
Subtract the reduction from the initial value:
\(560 - 280 = 280\)
4. Factor:
We then multiply the reduced value by the factor \( \frac{2}{6} \):
\(\frac{2}{6} = \frac{1}{3}\)
5. Multiplying Factor with Multiplier Value:
The next step is to multiply the factor by 660:
\(\frac{1}{3} \times 660 = 220\)
6. Final Value Calculation:
Finally, we multiply the reduced value by the product obtained from the previous step:
\(280 \times 220 = 61600\)
So, the reduced value is \(280\) and the final calculated result is \(61600\).
Therefore:
\[
\begin{array}{c}\text { Luneta } = \$[/tex] 560 - [(0.50)(\[tex]$ 560)] \\ \text { Luneta } = \$[/tex] 560 - \[tex]$ 280 \\
\text { Luneta } = \$[/tex] 280 \\
\text { Luneta final} = \[tex]$ 280 \times \left(\frac{2}{6} \times 660\right) \\
\text { Luneta final} = \$[/tex] 280 \times 220 = \$ 61600 \end{array}
\]
The final reduced and then calculated value carrying through step-by-step is:
[tex]\[
\boxed{(280.0, 61600.0)}
\][/tex]
