Answered

Get insightful responses to your questions quickly and easily on IDNLearn.com. Discover comprehensive answers to your questions from our community of experienced professionals.

Which is the setup to find the temperature 10 hours after sundown using the trendline [tex]y=-1.6x+72.4[/tex]?

A.
[tex]\[
\begin{array}{l}
(10)=-1.6x+72.4 \\
-72.4+10=-1.6x+72.4-72.4 \\
-62.4=-1.6x \\
\frac{-62.4}{1.6}=\frac{-1.6}{-1.6}x \\
-39=x
\end{array}
\][/tex]

B.
[tex]\[
\begin{array}{l}
y=-1.6(10)+72.4 \\
y=-16+72.4 \\
y=56.4
\end{array}
\][/tex]

C.
[tex]\[
\begin{array}{l}
(10)=-1.6x+72.4 \\
-72.4+10=-1.6x+72.4-72.4 \\
-62.4=-1.6x \\
\frac{-62.4}{1}=\frac{-1.6}{4}x
\end{array}
\][/tex]

Sagot :

GinnyAnsweridn
To find the temperature 10 hours after sundown using the trendline [tex]\( y = -1.6x + 72.4 \)[/tex], follow these steps:

1. Identify the value of [tex]\( x \)[/tex] given in the problem:
[tex]\[ x = 10 \text{ hours after sundown} \][/tex]

2. Substitute [tex]\( x = 10 \)[/tex] into the trendline equation [tex]\( y = -1.6x + 72.4 \)[/tex]:
[tex]\[ y = -1.6(10) + 72.4 \][/tex]

3. Perform the multiplication:
[tex]\[ y = -16 + 72.4 \][/tex]

4. Add the results to find the temperature:
[tex]\[ y = 56.4 \][/tex]

Hence, the temperature 10 hours after sundown is [tex]\( 56.4 \)[/tex] degrees.
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.