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Sagot :
To determine the number of zeros indicated by the values in the table representing the graph of a continuous function, we need to find the points where the function's value [tex]\( y \)[/tex] is equal to zero. These points are the x-values where the corresponding y-values are zero in the table.
Let's look at the table entries:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -3.0 & 8.40 \\ \hline -2.4 & 0.69 \\ \hline -1.8 & -0.39 \\ \hline -1.2 & 0.24 \\ \hline -0.6 & 0.46 \\ \hline 0 & 0 \\ \hline 0.6 & -0.46 \\ \hline 1.2 & -0.24 \\ \hline 1.8 & 0.39 \\ \hline 2.4 & -0.69 \\ \hline 3.0 & -8.40 \\ \hline \end{array} \][/tex]
From the table, we observe that the value of [tex]\( y \)[/tex] is zero at [tex]\( x = 0 \)[/tex]. This means that the function crosses the x-axis at this point.
Therefore, the continuous function represented by the given table of values has one zero.
The x-value at which this function has a zero is at [tex]\( x = 0 \)[/tex] where [tex]\( y = 0 \)[/tex].
So, the number of zeros is [tex]\( 1 \)[/tex] and the positions of the zeros are [tex]\((0, 0)\)[/tex].
Let's look at the table entries:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -3.0 & 8.40 \\ \hline -2.4 & 0.69 \\ \hline -1.8 & -0.39 \\ \hline -1.2 & 0.24 \\ \hline -0.6 & 0.46 \\ \hline 0 & 0 \\ \hline 0.6 & -0.46 \\ \hline 1.2 & -0.24 \\ \hline 1.8 & 0.39 \\ \hline 2.4 & -0.69 \\ \hline 3.0 & -8.40 \\ \hline \end{array} \][/tex]
From the table, we observe that the value of [tex]\( y \)[/tex] is zero at [tex]\( x = 0 \)[/tex]. This means that the function crosses the x-axis at this point.
Therefore, the continuous function represented by the given table of values has one zero.
The x-value at which this function has a zero is at [tex]\( x = 0 \)[/tex] where [tex]\( y = 0 \)[/tex].
So, the number of zeros is [tex]\( 1 \)[/tex] and the positions of the zeros are [tex]\((0, 0)\)[/tex].
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