Join the IDNLearn.com community and start finding the answers you need today. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.

Which expression is equivalent to [tex] \frac{-18 a^{-2} b^5}{-12 a^{-4} b^{-6}} ? [/tex] Assume [tex] a \neq 0, b \neq 0 [/tex].

A. [tex] \frac{2 a^2 b^{11}}{3} [/tex]
B. [tex] \frac{2 a^2 b^{30}}{3} [/tex]
C. [tex] \frac{3 a^2 b^{11}}{2} [/tex]
D. [tex] \frac{3 a^2 b^{30}}{2} [/tex]


Sagot :

To simplify the given expression [tex]\(\frac{-18 a^{-2} b^5}{-12 a^{-4} b^{-6}}\)[/tex], we will proceed step by step.

1. Simplify the coefficients:

The coefficients are [tex]\(-18\)[/tex] in the numerator and [tex]\(-12\)[/tex] in the denominator.

[tex]\[ \frac{-18}{-12} = \frac{18}{12} = \frac{3}{2} \][/tex]

The simplified coefficient is therefore [tex]\(\frac{3}{2}\)[/tex].

2. Simplify the variable [tex]\(a\)[/tex]:

The numerator has [tex]\(a^{-2}\)[/tex] and the denominator has [tex]\(a^{-4}\)[/tex].

Using the properties of exponents, namely [tex]\(a^m / a^n = a^{m-n}\)[/tex],

[tex]\[ \frac{a^{-2}}{a^{-4}} = a^{-2 - (-4)} = a^{-2 + 4} = a^{2} \][/tex]

So, the simplified expression involving [tex]\(a\)[/tex] is [tex]\(a^2\)[/tex].

3. Simplify the variable [tex]\(b\)[/tex]:

The numerator has [tex]\(b^5\)[/tex] and the denominator has [tex]\(b^{-6}\)[/tex].

Again, using the properties of exponents,

[tex]\[ \frac{b^5}{b^{-6}} = b^{5 - (-6)} = b^{5 + 6} = b^{11} \][/tex]

So, the simplified expression involving [tex]\(b\)[/tex] is [tex]\(b^{11}\)[/tex].

4. Combine all parts:

Combining the simplified coefficient, [tex]\(a\)[/tex] term, and [tex]\(b\)[/tex] term, the simplified expression is:

[tex]\[ \frac{3}{2} \cdot a^2 \cdot b^{11} = \frac{3 a^2 b^{11}}{2} \][/tex]

Therefore, the equivalent expression to [tex]\(\frac{-18 a^{-2} b^5}{-12 a^{-4} b^{-6}}\)[/tex] is:

[tex]\[ \boxed{\frac{3 a^2 b^{11}}{2}} \][/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.