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If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a [tex]\(\square\)[/tex] chance that the offspring will be heterozygous.
\begin{tabular}{|c|c|c|}
\hline & W & w \\
\hline w & Ww & ww \\
\hline w & Ww & ww \\
\hline
\end{tabular}

If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is [tex]\(\square\)[/tex].
\begin{tabular}{|c|c|c|}
\hline & W & w \\
\hline [tex]$W$[/tex] & WW & Ww \\
\hline W & WW & Ww \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
Sure, let's look at each part of the question step by step:

1. First Part: Heterozygous Male (Ww) x Homozygous Recessive Female (ww)

The provided Punnett Square for this cross is:
[tex]\[ \begin{tabular}{|c|c|c|} \hline & W & w \\ \hline w & Ww & ww \\ \hline w & Ww & ww \\ \hline \end{tabular} \][/tex]

From this Punnett Square, we see the possible offspring are:
- Ww (heterozygous)
- Ww (heterozygous)
- ww (homozygous recessive)
- ww (homozygous recessive)

Out of these four possible outcomes, two are heterozygous (Ww) and two are homozygous recessive (ww). Therefore, half or 50% of the offspring will be heterozygous.

So, the correct answer is:

If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that 50% of the offspring will be heterozygous.

2. Second Part: Heterozygous (Ww) x Homozygous Dominant (WW)

The provided Punnett Square for this cross is:
[tex]\[ \begin{tabular}{|c|c|c|} \hline & W & w \\ \hline $W$ & WW & Ww \\ \hline W & WW & Ww \\ \hline \end{tabular} \][/tex]

From this Punnett Square, we can see the possible offspring are:
- WW (homozygous dominant)
- Ww (heterozygous)
- WW (homozygous dominant)
- Ww (heterozygous)

None of these offspring are homozygous recessive (ww). Therefore, the probability of having a homozygous recessive offspring is 0%.

So, the correct answer is:

If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0%.

Therefore, the fully completed answer is:

If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that 50% of the offspring will be heterozygous.

If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is 0%.
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