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EXAMPLE 2

Given [tex]G(x) = 3x^2 + 7[/tex], find [tex]G(-3)[/tex].

Solution:
[tex]\[
\begin{array}{l}
G(-3) = 3(-3)^2 + 7 \\
G(-3) = 3(9) + 7 \\
G(-3) = 27 + 7 \\
G(-3) = 34
\end{array}
\][/tex]

Simplify the right side.

Sagot :

GinnyAnsweridn
To find [tex]\( G(-3) \)[/tex] for the function [tex]\( G(x) = 3x^2 + 7 \)[/tex], follow these steps:

1. Substitute the value [tex]\( -3 \)[/tex] for [tex]\( x \)[/tex] in the function [tex]\( G(x) \)[/tex].
[tex]\[ G(-3) = 3(-3)^2 + 7 \][/tex]

2. Calculate the square of [tex]\( -3 \)[/tex]:
[tex]\[ (-3)^2 = 9 \][/tex]

3. Multiply the result by 3:
[tex]\[ 3 \times 9 = 27 \][/tex]

4. Add 7 to the product:
[tex]\[ 27 + 7 = 34 \][/tex]

Thus, the value of [tex]\( G(-3) \)[/tex] is:
[tex]\[ G(-3) = 34 \][/tex]
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