Certainly! Let's go through each part of the problem step-by-step.
### Part 1: Equivalent Fractions
To find equivalent fractions, you can multiply the numerator and denominator by the same number. Here are two examples:
1. First Equivalent Fraction:
Multiply both the numerator (13) and the denominator (25) by 2:
[tex]\[
\frac{13 \times 2}{25 \times 2} = \frac{26}{50}
\][/tex]
2. Second Equivalent Fraction:
Multiply both the numerator (13) and the denominator (25) by 4:
[tex]\[
\frac{13 \times 4}{25 \times 4} = \frac{52}{100}
\][/tex]
So, the two equivalent fractions are [tex]\(\frac{26}{50}\)[/tex] and [tex]\(\frac{52}{100}\)[/tex].
### Part 2: Decimal Fraction
To convert the fraction [tex]\(\frac{13}{25}\)[/tex] to a decimal, you simply divide the numerator by the denominator:
[tex]\[
\frac{13}{25} = 0.52
\][/tex]
So, the decimal fraction for [tex]\(\frac{13}{25}\)[/tex] is [tex]\(0.52\)[/tex].
### Part 3: Percentage and Pass Status
To convert a fraction to a percentage, multiply the decimal form by 100:
[tex]\[
0.52 \times 100 = 52\%
\][/tex]
So, Keenan's percentage mark is [tex]\(52\%\)[/tex].
The passing percentage for the test is [tex]\(40\%\)[/tex]. Since [tex]\(52\%\)[/tex] is greater than [tex]\(40\%\)[/tex], Keenan did pass the test.
### Summary
- Two equivalent fractions for [tex]\(\frac{13}{25}\)[/tex] are [tex]\(\frac{26}{50}\)[/tex] and [tex]\(\frac{52}{100}\)[/tex].
- The decimal fraction of [tex]\(\frac{13}{25}\)[/tex] is [tex]\(0.52\)[/tex].
- Keenan's percentage is [tex]\(52\%\)[/tex], which means he passed the test as this is above the pass mark of [tex]\(40\%\)[/tex].
