IDNLearn.com offers a comprehensive solution for finding accurate answers quickly. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.
Sagot :
Sure, let's solve the given expression step-by-step:
Given expression:
[tex]\[ (2x - 3)(x + 5) \][/tex]
We will use the distributive property (also known as the FOIL method for binomials) to expand this expression.
1. First, distribute [tex]\(2x\)[/tex] in [tex]\(2x - 3\)[/tex] to each term in [tex]\(x + 5\)[/tex]:
[tex]\[ 2x \cdot x + 2x \cdot 5 \][/tex]
which simplifies to:
[tex]\[ 2x^2 + 10x \][/tex]
2. Next, distribute [tex]\(-3\)[/tex] in [tex]\(2x - 3\)[/tex] to each term in [tex]\(x + 5\)[/tex]:
[tex]\[ -3 \cdot x - 3 \cdot 5 \][/tex]
which simplifies to:
[tex]\[ -3x - 15 \][/tex]
3. Combine all the terms from the two distributive steps:
[tex]\[ 2x^2 + 10x - 3x - 15 \][/tex]
4. Now, combine like terms:
[tex]\[ 2x^2 + (10x - 3x) - 15 \][/tex]
which simplifies to:
[tex]\[ 2x^2 + 7x - 15 \][/tex]
So, the expanded form of the given expression [tex]\((2x - 3)(x + 5)\)[/tex] is:
[tex]\[ 2x^2 + 7x - 15 \][/tex]
Given expression:
[tex]\[ (2x - 3)(x + 5) \][/tex]
We will use the distributive property (also known as the FOIL method for binomials) to expand this expression.
1. First, distribute [tex]\(2x\)[/tex] in [tex]\(2x - 3\)[/tex] to each term in [tex]\(x + 5\)[/tex]:
[tex]\[ 2x \cdot x + 2x \cdot 5 \][/tex]
which simplifies to:
[tex]\[ 2x^2 + 10x \][/tex]
2. Next, distribute [tex]\(-3\)[/tex] in [tex]\(2x - 3\)[/tex] to each term in [tex]\(x + 5\)[/tex]:
[tex]\[ -3 \cdot x - 3 \cdot 5 \][/tex]
which simplifies to:
[tex]\[ -3x - 15 \][/tex]
3. Combine all the terms from the two distributive steps:
[tex]\[ 2x^2 + 10x - 3x - 15 \][/tex]
4. Now, combine like terms:
[tex]\[ 2x^2 + (10x - 3x) - 15 \][/tex]
which simplifies to:
[tex]\[ 2x^2 + 7x - 15 \][/tex]
So, the expanded form of the given expression [tex]\((2x - 3)(x + 5)\)[/tex] is:
[tex]\[ 2x^2 + 7x - 15 \][/tex]
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.