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Question 5, Part 1 of 3

Write the equation in slope-intercept form. Then find the slope and [tex]$y$[/tex]-intercept.

[tex]$
y = 9
$[/tex]

Write the equation in slope-intercept form.
[tex]$\square$[/tex]
(Type an equation. Type your answer in slope-intercept form.)

Sagot :

GinnyAnsweridn
Let's start by analyzing the given equation [tex]\( y = 9 \)[/tex].

The slope-intercept form of a linear equation is generally written as:
[tex]\[ y = mx + b \][/tex]
where [tex]\( m \)[/tex] is the slope of the line and [tex]\( b \)[/tex] is the y-intercept.

In this given equation, [tex]\( y = 9 \)[/tex], there is no [tex]\( x \)[/tex] term present. We can rewrite it in slope-intercept form by considering that the coefficient of [tex]\( x \)[/tex] is actually 0. Thus, it becomes:
[tex]\[ y = 0x + 9 \][/tex]

So the equation in slope-intercept form is:
[tex]\[ y = 0x + 9 \][/tex]

Moving on, let's identify the slope and the y-intercept:
- The slope [tex]\( m \)[/tex] is the coefficient of [tex]\( x \)[/tex]. Here, [tex]\( m = 0 \)[/tex].
- The y-intercept [tex]\( b \)[/tex] is the constant term. Here, [tex]\( b = 9 \)[/tex].

Therefore, the slope-intercept form of the equation is:
[tex]\[ y = 0x + 9 \][/tex]
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