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What is the factorization of the expression below?

[tex]\[ 16x^2 - 25y^2 \][/tex]


Sagot :

To factorize the expression [tex]\( 16x^2 - 25y^2 \)[/tex], we can recognize that it is a difference of squares. The difference of squares formula is:

[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]

In this given expression, we have:

[tex]\[ 16x^2 - 25y^2 \][/tex]

First, we observe that both [tex]\( 16x^2 \)[/tex] and [tex]\( 25y^2 \)[/tex] are perfect squares.

1. We identify the square roots of each term:
- The square root of [tex]\( 16x^2 \)[/tex] is [tex]\( 4x \)[/tex].
- The square root of [tex]\( 25y^2 \)[/tex] is [tex]\( 5y \)[/tex].

2. We now apply the difference of squares formula:
- We replace [tex]\( a \)[/tex] with [tex]\( 4x \)[/tex].
- We replace [tex]\( b \)[/tex] with [tex]\( 5y \)[/tex].

Using the formula [tex]\( a^2 - b^2 = (a - b)(a + b) \)[/tex], we get:

[tex]\[ 16x^2 - 25y^2 = (4x - 5y)(4x + 5y) \][/tex]

Thus, the factorization of the expression [tex]\( 16x^2 - 25y^2 \)[/tex] is:

[tex]\[ (4x - 5y)(4x + 5y) \][/tex]