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Begin by distributing the real term of the first complex number, [tex]\(2\)[/tex], to both terms of the second complex number, [tex]\(7 + 11i\)[/tex].

Type this result in [tex]\(a + bi\)[/tex] form, like this: [tex]\(4 + 2i\)[/tex]

[tex]\(\square\)[/tex]

Sagot :

GinnyAnsweridn
Certainly! Let's distribute the real term of the first complex number, 2, to both terms of the second complex number, [tex]\(7 + 11i\)[/tex].

First, distribute 2 to the real part, 7:
[tex]\[ 2 \times 7 = 14 \][/tex]

Next, distribute 2 to the imaginary part, 11i:
[tex]\[ 2 \times 11i = 22i \][/tex]

Now, combining these results, we get:
[tex]\[ 14 + 22i \][/tex]

So the result in [tex]\(a + bi\)[/tex] form is:
[tex]\[ 14 + 22i \][/tex]
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