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What is the solution to this system of equations?

[tex]\[
\left\{
\begin{array}{c}
2y + 4x = -8 \\
-y - 2x = 4
\end{array}
\right.
\][/tex]

A. (0, 2)
B. No Solution
C. Infinite Solutions


Sagot :

Let's analyze and solve the given system of equations:

[tex]\[ \left\{\begin{array}{c} 2y + 4x = -8 \\ -y - 2x = 4 \end{array}\right. \][/tex]

We will solve this system using the substitution or elimination method step-by-step. Let's start with the elimination method.

### Step 1: Align the system of equations

Let's write the system of equations again for clarity:

1. [tex]\(2y + 4x = -8\)[/tex]
2. [tex]\(-y - 2x = 4\)[/tex]

### Step 2: Eliminate one variable

We can eliminate one variable by adding or subtracting the equations. To do this, we'll first multiply the second equation by 2 to make the coefficients of [tex]\(y\)[/tex] equal in magnitude but opposite in sign:

[tex]\[2(-y - 2x) = 2(4)\][/tex]

This results in:

[tex]\[-2y - 4x = 8\][/tex]

Now we have the system:

1. [tex]\(2y + 4x = -8\)[/tex]
2. [tex]\(-2y - 4x = 8\)[/tex]

### Step 3: Add the equations

Next, we add the two equations together to eliminate [tex]\(y\)[/tex]:

[tex]\[ (2y + 4x) + (-2y - 4x) = -8 + 8 \][/tex]

This simplifies to:

[tex]\[ 0 = 0 \][/tex]

### Step 4: Interpret the result

The equation [tex]\(0 = 0\)[/tex] is always true, which indicates that the system of equations is dependent, and every point on one line is also a point on the other line.

This means that the two equations represent the same line, and therefore, there are infinite solutions to this system.

### Conclusion

The given system of equations does not have a single unique solution or no solution. Because it is consistent and dependent, the solution is:

[tex]\[ \text{Infinite Solutions} \][/tex]

Thus, the correct answer is:

[tex]\[ \text{Infinite Solutions} \][/tex]