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Find the difference of functions [tex]s[/tex] and [tex]r[/tex] shown.

[tex]\[
\begin{array}{l}
r(x) = -x^2 + 3x \\
s(x) = 2x + 1 \\
(s - r)(x) = \square
\end{array}
\][/tex]


Sagot :

To find the difference between the functions [tex]\(s(x)\)[/tex] and [tex]\(r(x)\)[/tex], we need to subtract [tex]\(r(x)\)[/tex] from [tex]\(s(x)\)[/tex]. Let's define the functions:

[tex]\[ r(x) = -x^2 + 3x \][/tex]
[tex]\[ s(x) = 2x + 1 \][/tex]

We aim to find [tex]\((s - r)(x)\)[/tex]:

[tex]\[ (s - r)(x) = s(x) - r(x) \][/tex]

Substitute [tex]\(r(x)\)[/tex] and [tex]\(s(x)\)[/tex] into the equation:

[tex]\[ (s - r)(x) = (2x + 1) - (-x^2 + 3x) \][/tex]

Distribute the negative sign through the [tex]\(r(x)\)[/tex] term:

[tex]\[ (s - r)(x) = 2x + 1 + x^2 - 3x \][/tex]

Now, combine like terms:

[tex]\[ (s - r)(x) = x^2 + (2x - 3x) + 1 \][/tex]

Simplify the expression inside the parentheses:

[tex]\[ (s - r)(x) = x^2 - x + 1 \][/tex]

Hence, the difference [tex]\((s - r)(x)\)[/tex] is:

[tex]\[ (s - r)(x) = x^2 - x + 1 \][/tex]

This is the simplified form of the resulting function when subtracting [tex]\(r(x)\)[/tex] from [tex]\(s(x)\)[/tex].