Find the best solutions to your problems with the help of IDNLearn.com's expert users. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.
Sagot :
To find the expression for [tex]\( (f \circ g)(x) \)[/tex], we need to apply the function [tex]\( g \)[/tex] first, and then apply the function [tex]\( f \)[/tex] to the result of [tex]\( g \)[/tex].
Given:
[tex]\[ f(x) = 3x + 2 \][/tex]
[tex]\[ g(x) = x^2 + 1 \][/tex]
1. First, evaluate [tex]\( g(x) \)[/tex]:
[tex]\[ g(x) = x^2 + 1 \][/tex]
2. Now, substitute [tex]\( g(x) \)[/tex] into [tex]\( f \)[/tex]:
[tex]\[ (f \circ g)(x) = f(g(x)) \][/tex]
The next step is to replace [tex]\( x \)[/tex] in [tex]\( f(x) = 3x + 2 \)[/tex] with [tex]\( g(x) \)[/tex]:
[tex]\[ (f \circ g)(x) = f(g(x)) = f(x^2 + 1) \][/tex]
3. Substitute [tex]\( x^2 + 1 \)[/tex] into [tex]\( f \)[/tex] in place of [tex]\( x \)[/tex]:
[tex]\[ f(x^2 + 1) = 3(x^2 + 1) + 2 \][/tex]
4. Distribute and simplify the expression:
[tex]\[ 3(x^2 + 1) + 2 = 3x^2 + 3 + 2 = 3x^2 + 5 \][/tex]
Therefore, the expression equivalent to [tex]\( (f \circ g)(x) \)[/tex] is:
[tex]\[ (f \circ g)(x) = 3x^2 + 5 \][/tex]
Given:
[tex]\[ f(x) = 3x + 2 \][/tex]
[tex]\[ g(x) = x^2 + 1 \][/tex]
1. First, evaluate [tex]\( g(x) \)[/tex]:
[tex]\[ g(x) = x^2 + 1 \][/tex]
2. Now, substitute [tex]\( g(x) \)[/tex] into [tex]\( f \)[/tex]:
[tex]\[ (f \circ g)(x) = f(g(x)) \][/tex]
The next step is to replace [tex]\( x \)[/tex] in [tex]\( f(x) = 3x + 2 \)[/tex] with [tex]\( g(x) \)[/tex]:
[tex]\[ (f \circ g)(x) = f(g(x)) = f(x^2 + 1) \][/tex]
3. Substitute [tex]\( x^2 + 1 \)[/tex] into [tex]\( f \)[/tex] in place of [tex]\( x \)[/tex]:
[tex]\[ f(x^2 + 1) = 3(x^2 + 1) + 2 \][/tex]
4. Distribute and simplify the expression:
[tex]\[ 3(x^2 + 1) + 2 = 3x^2 + 3 + 2 = 3x^2 + 5 \][/tex]
Therefore, the expression equivalent to [tex]\( (f \circ g)(x) \)[/tex] is:
[tex]\[ (f \circ g)(x) = 3x^2 + 5 \][/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.