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Given the functions

[tex]\[ g(x) = \frac{x+1}{x-2} \][/tex]
and
[tex]\[ h(x) = 4 - x \][/tex]

what is the value of [tex]\((g \circ h)(-3)\)[/tex]?


Sagot :

To find the value of [tex]\((g \circ h)(-3)\)[/tex], we need to evaluate [tex]\(g\)[/tex] at the value of [tex]\(h(-3)\)[/tex]. Follow these steps:

1. Evaluate [tex]\(h(-3)\)[/tex]:
The function [tex]\(h(x)\)[/tex] is given by:
[tex]\[ h(x) = 4 - x \][/tex]
Substitute [tex]\(x = -3\)[/tex] into [tex]\(h(x)\)[/tex]:
[tex]\[ h(-3) = 4 - (-3) = 4 + 3 = 7 \][/tex]
Therefore, [tex]\(h(-3) = 7\)[/tex].

2. Evaluate [tex]\(g(7)\)[/tex]:
The function [tex]\(g(x)\)[/tex] is given by:
[tex]\[ g(x) = \frac{x + 1}{x - 2} \][/tex]
Substitute [tex]\(x = 7\)[/tex] into [tex]\(g(x)\)[/tex]:
[tex]\[ g(7) = \frac{7 + 1}{7 - 2} = \frac{8}{5} = 1.6 \][/tex]
Therefore, [tex]\(g(7) = 1.6\)[/tex].

So, the value of [tex]\((g \circ h)(-3)\)[/tex] is [tex]\(1.6\)[/tex].
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