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Sagot :
To solve the given equation [tex]\(5c - 2 = 3c\)[/tex] and find the value of [tex]\(24c\)[/tex], follow these steps:
1. Isolate the variable [tex]\(c\)[/tex]:
[tex]\[ 5c - 2 = 3c \][/tex]
2. Subtract [tex]\(3c\)[/tex] from both sides to get all terms involving [tex]\(c\)[/tex] on one side:
[tex]\[ 5c - 3c - 2 = 3c - 3c \][/tex]
[tex]\[ 2c - 2 = 0 \][/tex]
3. Add 2 to both sides to remove the constant term on the left side:
[tex]\[ 2c - 2 + 2 = 0 + 2 \][/tex]
[tex]\[ 2c = 2 \][/tex]
4. Divide both sides by 2 to solve for [tex]\(c\)[/tex]:
[tex]\[ \frac{2c}{2} = \frac{2}{2} \][/tex]
[tex]\[ c = 1 \][/tex]
5. Now that we have the value of [tex]\(c\)[/tex], we need to find [tex]\(24c\)[/tex]:
[tex]\[ 24c = 24 \times 1 \][/tex]
[tex]\[ 24c = 24 \][/tex]
Therefore, the value of [tex]\(24c\)[/tex] is [tex]\(\boxed{24}\)[/tex].
1. Isolate the variable [tex]\(c\)[/tex]:
[tex]\[ 5c - 2 = 3c \][/tex]
2. Subtract [tex]\(3c\)[/tex] from both sides to get all terms involving [tex]\(c\)[/tex] on one side:
[tex]\[ 5c - 3c - 2 = 3c - 3c \][/tex]
[tex]\[ 2c - 2 = 0 \][/tex]
3. Add 2 to both sides to remove the constant term on the left side:
[tex]\[ 2c - 2 + 2 = 0 + 2 \][/tex]
[tex]\[ 2c = 2 \][/tex]
4. Divide both sides by 2 to solve for [tex]\(c\)[/tex]:
[tex]\[ \frac{2c}{2} = \frac{2}{2} \][/tex]
[tex]\[ c = 1 \][/tex]
5. Now that we have the value of [tex]\(c\)[/tex], we need to find [tex]\(24c\)[/tex]:
[tex]\[ 24c = 24 \times 1 \][/tex]
[tex]\[ 24c = 24 \][/tex]
Therefore, the value of [tex]\(24c\)[/tex] is [tex]\(\boxed{24}\)[/tex].
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