Discover how IDNLearn.com can help you find the answers you need quickly and easily. Our platform provides prompt, accurate answers from experts ready to assist you with any question you may have.

1. If [tex]\( 0^{\circ} \ \textless \ \theta \ \textless \ 90^{\circ} \)[/tex] and [tex]\( \cos \theta = \frac{11}{61} \)[/tex], find [tex]\( \cot \theta \)[/tex] using trigonometric identities.

A. [tex]\( \frac{11}{60} \)[/tex]
B. [tex]\( \frac{60}{11} \)[/tex]
C. [tex]\( \frac{11}{61} \)[/tex]
D. [tex]\( \frac{61}{11} \)[/tex]


Sagot :

To solve for [tex]\(\cot \theta\)[/tex] given that the angle [tex]\(\theta\)[/tex] lies in the range [tex]\(0^\circ < \theta < 90^\circ\)[/tex] and [tex]\(\cos \theta = \frac{11}{61}\)[/tex], we follow these steps using trigonometric identities:

1. Identify the components of the right triangle:
- We interpret [tex]\(\cos \theta = \frac{11}{61}\)[/tex] based on the definition of cosine in a right triangle:
[tex]\[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}. \][/tex]
This tells us:
[tex]\[ \text{adjacent} = 11 \quad \text{and} \quad \text{hypotenuse} = 61. \][/tex]

2. Find the opposite side of the triangle using the Pythagorean theorem:
- The Pythagorean theorem states:
[tex]\[ \text{opposite}^2 + \text{adjacent}^2 = \text{hypotenuse}^2. \][/tex]
Substituting the known values:
[tex]\[ \text{opposite}^2 + 11^2 = 61^2. \][/tex]
[tex]\[ \text{opposite}^2 + 121 = 3721. \][/tex]
Solving for [tex]\(\text{opposite}^2\)[/tex]:
[tex]\[ \text{opposite}^2 = 3721 - 121 = 3600, \][/tex]
hence:
[tex]\[ \text{opposite} = \sqrt{3600} = 60. \][/tex]

3. Determine [tex]\(\cot \theta\)[/tex]:
- We use the definition of cotangent:
[tex]\[ \cot \theta = \frac{1}{\tan \theta} = \frac{\text{adjacent}}{\text{opposite}}. \][/tex]
With the values we have determined:
[tex]\[ \cot \theta = \frac{11}{60}. \][/tex]

Therefore, the correct value of [tex]\(\cot \theta\)[/tex] given [tex]\(\cos \theta = \frac{11}{61}\)[/tex] is:
[tex]\[ \frac{11}{60}. \][/tex]

The correct option is:
[tex]\[ \frac{11}{60}. \][/tex]