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Sagot :
Sure! Let's evaluate the integral of a given function with respect to [tex]\( x \)[/tex] over the interval [tex]\([x+9, 2x+4]\)[/tex].
The integral to evaluate is:
[tex]\[ \int_{x+9}^{2x+4} 1 \, dx \][/tex]
Here, the integrand is the constant function [tex]\( 1 \)[/tex]. When integrating a constant, the result is the constant multiplied by the length of the integration interval. Therefore, we need to determine the length of the interval from [tex]\( x+9 \)[/tex] to [tex]\( 2x+4 \)[/tex].
The length of the interval can be found by subtracting the lower bound from the upper bound:
[tex]\[ \text{Length of interval} = (2x + 4) - (x + 9) \][/tex]
Simplify the expression inside the parentheses:
[tex]\[ (2x + 4) - (x + 9) = 2x + 4 - x - 9 \][/tex]
[tex]\[ = x - 5 \][/tex]
Now, since the integrand is [tex]\( 1 \)[/tex], the integral of [tex]\( 1 \)[/tex] over the interval [tex]\([x+9, 2x+4]\)[/tex] is simply the length of the interval:
[tex]\[ \int_{x+9}^{2x+4} 1 \, dx = x - 5 \][/tex]
So, the value of the given integral is:
[tex]\[ x - 5 \][/tex]
The integral to evaluate is:
[tex]\[ \int_{x+9}^{2x+4} 1 \, dx \][/tex]
Here, the integrand is the constant function [tex]\( 1 \)[/tex]. When integrating a constant, the result is the constant multiplied by the length of the integration interval. Therefore, we need to determine the length of the interval from [tex]\( x+9 \)[/tex] to [tex]\( 2x+4 \)[/tex].
The length of the interval can be found by subtracting the lower bound from the upper bound:
[tex]\[ \text{Length of interval} = (2x + 4) - (x + 9) \][/tex]
Simplify the expression inside the parentheses:
[tex]\[ (2x + 4) - (x + 9) = 2x + 4 - x - 9 \][/tex]
[tex]\[ = x - 5 \][/tex]
Now, since the integrand is [tex]\( 1 \)[/tex], the integral of [tex]\( 1 \)[/tex] over the interval [tex]\([x+9, 2x+4]\)[/tex] is simply the length of the interval:
[tex]\[ \int_{x+9}^{2x+4} 1 \, dx = x - 5 \][/tex]
So, the value of the given integral is:
[tex]\[ x - 5 \][/tex]
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