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To determine which statement is true regarding the remaining vacation days for Matt and Linda, we will calculate the mean and median values for both of them.
### Step-by-Step Calculation:
#### 1. Data for Matt and Linda:
- Matt's vacation days at the end of each quarter: [13, 11, 7, 4]
- Linda's vacation days at the end of each quarter: [12, 11, 7, 0]
#### 2. Calculate the Mean:
- Mean for Matt:
[tex]\[ \text{mean}_{\text{Matt}} = \frac{13 + 11 + 7 + 4}{4} \][/tex]
Simplifying the numerator:
[tex]\[ 13 + 11 = 24 \][/tex]
[tex]\[ 24 + 7 = 31 \][/tex]
[tex]\[ 31 + 4 = 35 \][/tex]
Therefore,
[tex]\[ \text{mean}_{\text{Matt}} = \frac{35}{4} = 8.75 \][/tex]
- Mean for Linda:
[tex]\[ \text{mean}_{\text{Linda}} = \frac{12 + 11 + 7 + 0}{4} \][/tex]
Simplifying the numerator:
[tex]\[ 12 + 11 = 23 \][/tex]
[tex]\[ 23 + 7 = 30 \][/tex]
[tex]\[ 30 + 0 = 30 \][/tex]
Therefore,
[tex]\[ \text{mean}_{\text{Linda}} = \frac{30}{4} = 7.5 \][/tex]
#### 3. Calculate the Median:
- Median for Matt:
The ordered list of Matt’s vacation days is [4, 7, 11, 13]. The median is the average of the two middle numbers:
[tex]\[ \text{median}_{\text{Matt}} = \frac{7 + 11}{2} = \frac{18}{2} = 9.0 \][/tex]
- Median for Linda:
The ordered list of Linda’s vacation days is [0, 7, 11, 12]. The median is the average of the two middle numbers:
[tex]\[ \text{median}_{\text{Linda}} = \frac{7 + 11}{2} = \frac{18}{2} = 9.0 \][/tex]
### Comparison and Conclusion:
- Mean Comparison:
[tex]\[ \text{mean}_{\text{Matt}} = 8.75 > 7.5 = \text{mean}_{\text{Linda}} \][/tex]
- Median Comparison:
[tex]\[ \text{median}_{\text{Matt}} = 9.0 = 9.0 = \text{median}_{\text{Linda}} \][/tex]
Given these calculations, we can confirm that:
- The mean number of vacation days Matt has remaining is greater than the mean number of vacation days Linda has remaining.
- The median number of vacation days remaining for both Matt and Linda is the same.
Thus, the correct statement is:
D. The mean number of vacation days Matt has remaining is greater than the mean number of vacation days Linda has remaining.
### Step-by-Step Calculation:
#### 1. Data for Matt and Linda:
- Matt's vacation days at the end of each quarter: [13, 11, 7, 4]
- Linda's vacation days at the end of each quarter: [12, 11, 7, 0]
#### 2. Calculate the Mean:
- Mean for Matt:
[tex]\[ \text{mean}_{\text{Matt}} = \frac{13 + 11 + 7 + 4}{4} \][/tex]
Simplifying the numerator:
[tex]\[ 13 + 11 = 24 \][/tex]
[tex]\[ 24 + 7 = 31 \][/tex]
[tex]\[ 31 + 4 = 35 \][/tex]
Therefore,
[tex]\[ \text{mean}_{\text{Matt}} = \frac{35}{4} = 8.75 \][/tex]
- Mean for Linda:
[tex]\[ \text{mean}_{\text{Linda}} = \frac{12 + 11 + 7 + 0}{4} \][/tex]
Simplifying the numerator:
[tex]\[ 12 + 11 = 23 \][/tex]
[tex]\[ 23 + 7 = 30 \][/tex]
[tex]\[ 30 + 0 = 30 \][/tex]
Therefore,
[tex]\[ \text{mean}_{\text{Linda}} = \frac{30}{4} = 7.5 \][/tex]
#### 3. Calculate the Median:
- Median for Matt:
The ordered list of Matt’s vacation days is [4, 7, 11, 13]. The median is the average of the two middle numbers:
[tex]\[ \text{median}_{\text{Matt}} = \frac{7 + 11}{2} = \frac{18}{2} = 9.0 \][/tex]
- Median for Linda:
The ordered list of Linda’s vacation days is [0, 7, 11, 12]. The median is the average of the two middle numbers:
[tex]\[ \text{median}_{\text{Linda}} = \frac{7 + 11}{2} = \frac{18}{2} = 9.0 \][/tex]
### Comparison and Conclusion:
- Mean Comparison:
[tex]\[ \text{mean}_{\text{Matt}} = 8.75 > 7.5 = \text{mean}_{\text{Linda}} \][/tex]
- Median Comparison:
[tex]\[ \text{median}_{\text{Matt}} = 9.0 = 9.0 = \text{median}_{\text{Linda}} \][/tex]
Given these calculations, we can confirm that:
- The mean number of vacation days Matt has remaining is greater than the mean number of vacation days Linda has remaining.
- The median number of vacation days remaining for both Matt and Linda is the same.
Thus, the correct statement is:
D. The mean number of vacation days Matt has remaining is greater than the mean number of vacation days Linda has remaining.
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