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Sagot :
Sure, let's solve the equation step by step.
Given the equation:
[tex]\[ \frac{2x + 5}{3} = 7 \][/tex]
1. Clear the denominator: To eliminate the fraction, multiply both sides of the equation by 3.
[tex]\[ 3 \cdot \frac{2x + 5}{3} = 7 \cdot 3 \][/tex]
Simplifying this, we get:
[tex]\[ 2x + 5 = 21 \][/tex]
2. Isolate the term with [tex]\( x \)[/tex]: To isolate [tex]\( 2x \)[/tex], subtract 5 from both sides of the equation.
[tex]\[ 2x + 5 - 5 = 21 - 5 \][/tex]
Simplifying this, we get:
[tex]\[ 2x = 16 \][/tex]
3. Solve for [tex]\( x \)[/tex]: To find the value of [tex]\( x \)[/tex], divide both sides of the equation by 2.
[tex]\[ \frac{2x}{2} = \frac{16}{2} \][/tex]
Simplifying this, we get:
[tex]\[ x = 8 \][/tex]
Therefore, the solution to the equation [tex]\( \frac{2x + 5}{3} = 7 \)[/tex] is [tex]\( x = 8 \)[/tex].
Given the equation:
[tex]\[ \frac{2x + 5}{3} = 7 \][/tex]
1. Clear the denominator: To eliminate the fraction, multiply both sides of the equation by 3.
[tex]\[ 3 \cdot \frac{2x + 5}{3} = 7 \cdot 3 \][/tex]
Simplifying this, we get:
[tex]\[ 2x + 5 = 21 \][/tex]
2. Isolate the term with [tex]\( x \)[/tex]: To isolate [tex]\( 2x \)[/tex], subtract 5 from both sides of the equation.
[tex]\[ 2x + 5 - 5 = 21 - 5 \][/tex]
Simplifying this, we get:
[tex]\[ 2x = 16 \][/tex]
3. Solve for [tex]\( x \)[/tex]: To find the value of [tex]\( x \)[/tex], divide both sides of the equation by 2.
[tex]\[ \frac{2x}{2} = \frac{16}{2} \][/tex]
Simplifying this, we get:
[tex]\[ x = 8 \][/tex]
Therefore, the solution to the equation [tex]\( \frac{2x + 5}{3} = 7 \)[/tex] is [tex]\( x = 8 \)[/tex].
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