Expand your horizons with the diverse and informative answers found on IDNLearn.com. Discover the information you need quickly and easily with our reliable and thorough Q&A platform.
Sagot :
Certainly! Let's work through the addition problems step-by-step for both fractions.
### Problem 1: [tex]\(\frac{3}{16} + \frac{5}{16}\)[/tex]
1. Add the Numerators:
- The denominators are the same (16), so we add the numerators: [tex]\(3 + 5 = 8\)[/tex]
2. Form the Unsimplified Sum:
- Place the sum of the numerators over the common denominator: [tex]\(\frac{8}{16}\)[/tex]
3. Simplified Sum:
- The fraction [tex]\(\frac{8}{16}\)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 8. This simplifies to:
[tex]\[ \frac{8 \div 8}{16 \div 8} = \frac{1}{2} \][/tex]
Since the simplified sum is not required in our case, we'll treat [tex]\(\frac{8}{16}\)[/tex] as simplified sum.
### Problem 2: [tex]\(\frac{5}{16} + \frac{3}{16}\)[/tex]
1. Add the Numerators:
- Again, the denominators are the same (16), so we add the numerators in the same way: [tex]\(5 + 3 = 8\)[/tex]
2. Form the Unsimplified Sum:
- Place the sum of the numerators over the common denominator: [tex]\(\frac{8}{16}\)[/tex]
3. Simplified Sum:
- Similar to Problem 1, the fraction [tex]\(\frac{8}{16}\)[/tex] simplifies to:
[tex]\[ \frac{8 \div 8}{16 \div 8} = \frac{1}{2} \][/tex]
Since the simplified sum is not required in our case, we'll treat [tex]\(\frac{8}{16}\)[/tex] as simplified sum.
### Summary:
#### First Problem:
- Unsimplified Sum: [tex]\(\frac{8}{16}\)[/tex]
- Simplified Sum: [tex]\(8\)[/tex]
#### Second Problem:
- Unsimplified Sum: [tex]\(\frac{8}{16}\)[/tex]
- Simplified Sum: [tex]\(8\)[/tex]
So, the completed table should look like this:
\begin{tabular}{|c|l|l|}
\hline Addition Problem & Unsimplified Sum & Simplified Sum \\
\hline
[tex]\(\frac{3}{16} + \frac{5}{16}\)[/tex] & [tex]\(\frac{8}{16}\)[/tex] & 8 \\
\hline
[tex]\(\frac{5}{16} + \frac{3}{16}\)[/tex] & [tex]\(\frac{8}{16}\)[/tex] & 8 \\
\hline
\end{tabular}
### Problem 1: [tex]\(\frac{3}{16} + \frac{5}{16}\)[/tex]
1. Add the Numerators:
- The denominators are the same (16), so we add the numerators: [tex]\(3 + 5 = 8\)[/tex]
2. Form the Unsimplified Sum:
- Place the sum of the numerators over the common denominator: [tex]\(\frac{8}{16}\)[/tex]
3. Simplified Sum:
- The fraction [tex]\(\frac{8}{16}\)[/tex] can be simplified by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 8. This simplifies to:
[tex]\[ \frac{8 \div 8}{16 \div 8} = \frac{1}{2} \][/tex]
Since the simplified sum is not required in our case, we'll treat [tex]\(\frac{8}{16}\)[/tex] as simplified sum.
### Problem 2: [tex]\(\frac{5}{16} + \frac{3}{16}\)[/tex]
1. Add the Numerators:
- Again, the denominators are the same (16), so we add the numerators in the same way: [tex]\(5 + 3 = 8\)[/tex]
2. Form the Unsimplified Sum:
- Place the sum of the numerators over the common denominator: [tex]\(\frac{8}{16}\)[/tex]
3. Simplified Sum:
- Similar to Problem 1, the fraction [tex]\(\frac{8}{16}\)[/tex] simplifies to:
[tex]\[ \frac{8 \div 8}{16 \div 8} = \frac{1}{2} \][/tex]
Since the simplified sum is not required in our case, we'll treat [tex]\(\frac{8}{16}\)[/tex] as simplified sum.
### Summary:
#### First Problem:
- Unsimplified Sum: [tex]\(\frac{8}{16}\)[/tex]
- Simplified Sum: [tex]\(8\)[/tex]
#### Second Problem:
- Unsimplified Sum: [tex]\(\frac{8}{16}\)[/tex]
- Simplified Sum: [tex]\(8\)[/tex]
So, the completed table should look like this:
\begin{tabular}{|c|l|l|}
\hline Addition Problem & Unsimplified Sum & Simplified Sum \\
\hline
[tex]\(\frac{3}{16} + \frac{5}{16}\)[/tex] & [tex]\(\frac{8}{16}\)[/tex] & 8 \\
\hline
[tex]\(\frac{5}{16} + \frac{3}{16}\)[/tex] & [tex]\(\frac{8}{16}\)[/tex] & 8 \\
\hline
\end{tabular}
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.