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Sagot :
To determine the speed of a sound wave as it passes through the air, we can use the equation for the speed of a wave, which is given by:
[tex]\[ v = f \times \lambda \][/tex]
where:
- [tex]\( v \)[/tex] is the speed of the wave,
- [tex]\( f \)[/tex] is the frequency of the wave,
- [tex]\( \lambda \)[/tex] is the wavelength of the wave.
We are given that:
- The frequency [tex]\( f \)[/tex] of the sound wave is 220 Hz,
- The wavelength [tex]\( \lambda \)[/tex] of the sound wave in air is 1.6 meters.
Let us substitute the given values into the wave speed equation:
[tex]\[ v = 220 \, \text{Hz} \times 1.6 \, \text{m} \][/tex]
[tex]\[ v = 352 \, \text{m/s} \][/tex]
Therefore, the speed of the sound wave as it passes through the air is approximately 352 m/s.
Given the options:
A. [tex]\( 350 \, \text{m/s} \)[/tex]
B. [tex]\( 5,700 \, \text{m/s} \)[/tex]
C. [tex]\( 570 \, \text{m/s} \)[/tex]
D. [tex]\( 3,500 \, \text{m/s} \)[/tex]
The closest value to our calculated speed is:
A. [tex]\( 350 \, \text{m/s} \)[/tex]
Thus, the correct answer is:
A. [tex]\( 350 \, \text{m/s} \)[/tex]
[tex]\[ v = f \times \lambda \][/tex]
where:
- [tex]\( v \)[/tex] is the speed of the wave,
- [tex]\( f \)[/tex] is the frequency of the wave,
- [tex]\( \lambda \)[/tex] is the wavelength of the wave.
We are given that:
- The frequency [tex]\( f \)[/tex] of the sound wave is 220 Hz,
- The wavelength [tex]\( \lambda \)[/tex] of the sound wave in air is 1.6 meters.
Let us substitute the given values into the wave speed equation:
[tex]\[ v = 220 \, \text{Hz} \times 1.6 \, \text{m} \][/tex]
[tex]\[ v = 352 \, \text{m/s} \][/tex]
Therefore, the speed of the sound wave as it passes through the air is approximately 352 m/s.
Given the options:
A. [tex]\( 350 \, \text{m/s} \)[/tex]
B. [tex]\( 5,700 \, \text{m/s} \)[/tex]
C. [tex]\( 570 \, \text{m/s} \)[/tex]
D. [tex]\( 3,500 \, \text{m/s} \)[/tex]
The closest value to our calculated speed is:
A. [tex]\( 350 \, \text{m/s} \)[/tex]
Thus, the correct answer is:
A. [tex]\( 350 \, \text{m/s} \)[/tex]
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