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What is the value of this expression when [tex]$c=-4$[/tex] and [tex]$d=10$[/tex]?

[tex]\frac{1}{4}\left(c^3 + d^2\right)[/tex]

A. 2
B. 9
C. 21
D. 41


Sagot :

To find the value of the expression [tex]\(\frac{1}{4}\left(c^3 + d^2\right)\)[/tex] when [tex]\(c = -4\)[/tex] and [tex]\(d = 10\)[/tex], follow these steps:

1. Substitute the given values into the expression:
[tex]\[ \frac{1}{4} \left((-4)^3 + 10^2\right) \][/tex]

2. Calculate each part inside the parentheses:

- Find [tex]\((-4)^3\)[/tex] (the cube of -4):
[tex]\[ (-4)^3 = -64 \][/tex]

- Find [tex]\(10^2\)[/tex] (the square of 10):
[tex]\[ 10^2 = 100 \][/tex]

3. Add the results from inside the parentheses:
[tex]\[ -64 + 100 = 36 \][/tex]

4. Multiply the sum by [tex]\(\frac{1}{4}\)[/tex]:
[tex]\[ \frac{1}{4} \times 36 = 9 \][/tex]

So, the value of the expression [tex]\(\frac{1}{4}\left(c^3 + d^2\right)\)[/tex] when [tex]\(c = -4\)[/tex] and [tex]\(d = 10\)[/tex] is [tex]\(9\)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{9} \][/tex]
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