To determine the applied force on a spring that is stretched, we can use Hooke's Law. Hooke's Law gives a relationship between the force exerted by a spring and its displacement from the equilibrium position. The law is represented by the formula:
[tex]\[ F = k \cdot x \][/tex]
where:
- [tex]\( F \)[/tex] is the force applied on the spring,
- [tex]\( k \)[/tex] is the spring constant, which measures the stiffness of the spring,
- [tex]\( x \)[/tex] is the displacement or stretch distance of the spring from its equilibrium position.
In this problem, we are given the following data:
- The spring constant [tex]\( k \)[/tex] is 50 N/m.
- The stretch distance [tex]\( x \)[/tex] is 0.7 meters.
We can substitute these values into the formula to find the applied force:
[tex]\[ F = 50 \, \text{N/m} \cdot 0.7 \, \text{m} \][/tex]
Multiplying these values:
[tex]\[ F = 35 \, \text{N} \][/tex]
Thus, the applied force on the spring is [tex]\( 35 \, \text{N} \)[/tex].
