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A fruit fly population can be modeled by the equation [tex]P = 10(1.27)^t[/tex], where [tex]P[/tex] represents the number of fruit flies after [tex]t[/tex] days. What is the average rate of change of the population, rounded to the nearest hundredth, over the interval [tex][0, 10.5][/tex]? Include appropriate units in your answer.

Sagot :

To determine the average rate of change of the fruit fly population over the interval [tex]\([0, 10.5]\)[/tex], we'll use the given population model [tex]\(P=10(1.27)^t\)[/tex].

Here's the step-by-step solution:

1. Identify the initial and final times in the given interval:
[tex]\[ t_{\text{initial}} = 0, \quad t_{\text{final}} = 10.5 \][/tex]

2. Calculate the population at the initial time ([tex]\(t = 0\)[/tex]):
[tex]\[ P_{\text{initial}} = 10 \times (1.27)^0 = 10 \times 1 = 10 \][/tex]

3. Calculate the population at the final time ([tex]\(t = 10.5\)[/tex]):
[tex]\[ P_{\text{final}} = 10 \times (1.27)^{10.5} \approx 123.01 \][/tex]

4. Determine the average rate of change:
[tex]\[ \text{Average rate of change} = \frac{P_{\text{final}} - P_{\text{initial}}}{t_{\text{final}} - t_{\text{initial}}} \][/tex]

Plugging in the values:
[tex]\[ \text{Average rate of change} = \frac{123.01 - 10}{10.5 - 0} = \frac{113.01}{10.5} \approx 10.76 \][/tex]

5. Include appropriate units: Since [tex]\(P\)[/tex] represents the number of fruit flies and [tex]\(t\)[/tex] is in days, the average rate of change is in fruit flies per day.

Thus, the average rate of change of the population over the interval [tex]\([0, 10.5]\)[/tex] is approximately [tex]\(10.76\)[/tex] fruit flies per day.