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A scientist was investigating if differences in the frictional work performed on a model car can change depending on its mass (in grams) and whether the car moves up or down an inclined plane. They decided to measure the amount of frictional force experienced by the model car and the distance it traveled in meters. The scientists were able to evaluate the frictional work using the following data.

\begin{tabular}{|l|l|l|l|l|}
\hline
& Mass [tex]$(g)$[/tex] & Distance [tex]$(m)$[/tex] & Force [tex]$(N)$[/tex] & Work Done by Friction [tex]$(J)$[/tex] \\
\hline
Car going up the incline & 100 & 39 & 0.063 & 2.457 \\
\hline
Car going down the incline & 70 & 39 & 0.2309 & [tex]$? $[/tex] \\
\hline
\end{tabular}

It is known that the relationship between force and distance determines the work done by friction [tex]$\left(W_f\right)$[/tex]:
[tex]\[ W_{f} = f \cdot d \][/tex]
where:
[tex]\[ W_{f} = \text{work done by friction} \][/tex]
[tex]\[ f = \text{force} \][/tex]
[tex]\[ d = \text{distance} \][/tex]

Question:
How much work done by friction was exerted on the car as it moved down the inclined plane?

Sagot :

GinnyAnsweridn
Let's determine the work done by friction on the car as it moves down the inclined plane using the given data.

We are provided with the following information for the car moving down the incline:
- Distance traveled [tex]\( d = 39 \)[/tex] meters
- Frictional force [tex]\( f = 0.2309 \)[/tex] N

The formula to calculate the work done by friction [tex]\( W_f \)[/tex] is:
[tex]\[ W_f = f \times d \][/tex]

Substituting the given values into the formula, we get:
[tex]\[ W_f = 0.2309 \times 39 \][/tex]

When we perform this multiplication, we get the work done by the frictional force on the car:
[tex]\[ W_f = 9.0051 \text{ joules} \][/tex]

Therefore, the work done by friction as the car moved down the inclined plane is [tex]\( 9.0051 \)[/tex] joules.
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