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Sagot :
To multiply the given polynomials, [tex]\((5x^2 - 7)\)[/tex] and [tex]\((5x^2 + 7)\)[/tex], we will use the distributive property (also known as the FOIL method for binomials). Let's go through this step-by-step:
1. First, multiply the first terms of each binomial:
[tex]\[ (5x^2) \cdot (5x^2) = 25x^4 \][/tex]
2. Outer, multiply the outer terms of the binomials:
[tex]\[ (5x^2) \cdot 7 = 35x^2 \][/tex]
3. Inner, multiply the inner terms of the binomials:
[tex]\[ (-7) \cdot (5x^2) = -35x^2 \][/tex]
4. Last, multiply the last terms of each binomial:
[tex]\[ (-7) \cdot 7 = -49 \][/tex]
Now, add all the products together:
[tex]\[ 25x^4 + 35x^2 - 35x^2 - 49 \][/tex]
Notice that the middle terms [tex]\(+35x^2\)[/tex] and [tex]\(-35x^2\)[/tex] cancel each other out, leaving us with:
[tex]\[ 25x^4 - 49 \][/tex]
So, the product of the two polynomials [tex]\((5x^2 - 7)\)[/tex] and [tex]\((5x^2 + 7)\)[/tex] is:
[tex]\[ 25x^4 - 49 \][/tex]
Thus, when you arrange the answer in descending powers of [tex]\(x\)[/tex], you get:
[tex]\[ \boxed{25x^4 - 49} \][/tex]
1. First, multiply the first terms of each binomial:
[tex]\[ (5x^2) \cdot (5x^2) = 25x^4 \][/tex]
2. Outer, multiply the outer terms of the binomials:
[tex]\[ (5x^2) \cdot 7 = 35x^2 \][/tex]
3. Inner, multiply the inner terms of the binomials:
[tex]\[ (-7) \cdot (5x^2) = -35x^2 \][/tex]
4. Last, multiply the last terms of each binomial:
[tex]\[ (-7) \cdot 7 = -49 \][/tex]
Now, add all the products together:
[tex]\[ 25x^4 + 35x^2 - 35x^2 - 49 \][/tex]
Notice that the middle terms [tex]\(+35x^2\)[/tex] and [tex]\(-35x^2\)[/tex] cancel each other out, leaving us with:
[tex]\[ 25x^4 - 49 \][/tex]
So, the product of the two polynomials [tex]\((5x^2 - 7)\)[/tex] and [tex]\((5x^2 + 7)\)[/tex] is:
[tex]\[ 25x^4 - 49 \][/tex]
Thus, when you arrange the answer in descending powers of [tex]\(x\)[/tex], you get:
[tex]\[ \boxed{25x^4 - 49} \][/tex]
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