IDNLearn.com: Your reliable source for finding precise answers. Discover detailed answers to your questions with our extensive database of expert knowledge.
Sagot :
Sure, let's calculate the oxidation numbers of the atoms in sodium chlorite (NaClO₂).
### Step-by-Step Solution:
1. Identify the known oxidation numbers:
- Sodium (Na) usually has an oxidation number of +1.
- Oxygen (O) typically has an oxidation number of -2.
2. Let the oxidation number of chlorine (Cl) be [tex]\(x\)[/tex].
3. Set up the equation for the sum of the oxidation numbers in the compound:
- Sodium chlorite (NaClO₂) is a neutral molecule, so the sum of the oxidation numbers of all atoms must equal 0.
- The formula of sodium chlorite is NaClO₂. Thus, we get:
[tex]\[ \text{Oxidation number of Na} + \text{Oxidation number of Cl} + 2 \times \text{Oxidation number of O} = 0 \][/tex]
4. Substitute the known values into the equation:
- Using the known oxidation numbers:
[tex]\[ 1 + x + 2 \times (-2) = 0 \][/tex]
5. Solve for [tex]\(x\)[/tex] (the oxidation number of chlorine):
- Simplify the equation step-by-step:
[tex]\[ 1 + x - 4 = 0 \][/tex]
[tex]\[ x - 3 = 0 \][/tex]
[tex]\[ x = +3 \][/tex]
- Therefore, the oxidation number of chlorine (Cl) in sodium chlorite is +3.
### Conclusion:
- The oxidation number of sodium (Na) is +1.
- The oxidation number of oxygen (O) is -2.
- The oxidation number of chlorine (Cl) is +3.
### Verification:
- Summing these oxidation numbers:
[tex]\[ 1 + 3 + 2 \times (-2) = 1 + 3 - 4 = 0 \][/tex]
- The oxidation numbers add up to 0, confirming that the calculations are correct for the neutral compound.
Thus, the oxidation numbers are:
- Sodium (Na): +1
- Oxygen (O): -2
- Chlorine (Cl): +3
Total oxidation state balance: 0
### Step-by-Step Solution:
1. Identify the known oxidation numbers:
- Sodium (Na) usually has an oxidation number of +1.
- Oxygen (O) typically has an oxidation number of -2.
2. Let the oxidation number of chlorine (Cl) be [tex]\(x\)[/tex].
3. Set up the equation for the sum of the oxidation numbers in the compound:
- Sodium chlorite (NaClO₂) is a neutral molecule, so the sum of the oxidation numbers of all atoms must equal 0.
- The formula of sodium chlorite is NaClO₂. Thus, we get:
[tex]\[ \text{Oxidation number of Na} + \text{Oxidation number of Cl} + 2 \times \text{Oxidation number of O} = 0 \][/tex]
4. Substitute the known values into the equation:
- Using the known oxidation numbers:
[tex]\[ 1 + x + 2 \times (-2) = 0 \][/tex]
5. Solve for [tex]\(x\)[/tex] (the oxidation number of chlorine):
- Simplify the equation step-by-step:
[tex]\[ 1 + x - 4 = 0 \][/tex]
[tex]\[ x - 3 = 0 \][/tex]
[tex]\[ x = +3 \][/tex]
- Therefore, the oxidation number of chlorine (Cl) in sodium chlorite is +3.
### Conclusion:
- The oxidation number of sodium (Na) is +1.
- The oxidation number of oxygen (O) is -2.
- The oxidation number of chlorine (Cl) is +3.
### Verification:
- Summing these oxidation numbers:
[tex]\[ 1 + 3 + 2 \times (-2) = 1 + 3 - 4 = 0 \][/tex]
- The oxidation numbers add up to 0, confirming that the calculations are correct for the neutral compound.
Thus, the oxidation numbers are:
- Sodium (Na): +1
- Oxygen (O): -2
- Chlorine (Cl): +3
Total oxidation state balance: 0
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.