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Answer the following four questions. Pay attention to significant figures, and show your work!

1. While doing a lab, a student found the density of a piece of pure aluminum to be 2.85 g/cm³. The accepted value for the density of aluminum is 2.70 g/cm³. What was the student's percent error?


Sagot :

Sure, let’s go through the calculation of the percent error step-by-step:

1. Identify the known values:

- The accepted value for the density of aluminum is 2.70 g/cm³.
- The student's measured value for the density of aluminum is 2.85 g/cm³.

2. Understand the percent error formula:

The percent error is calculated using the formula:
[tex]\[ \text{Percent Error} = \left| \frac{\text{Experimental Value} - \text{Accepted Value}}{\text{Accepted Value}} \right| \times 100 \][/tex]

3. Insert the known values into the formula:

[tex]\[ \text{Percent Error} = \left| \frac{2.85 \, \text{g/cm}^3 - 2.70 \, \text{g/cm}^3}{2.70 \, \text{g/cm}^3} \right| \times 100 \][/tex]

4. Subtract the accepted value from the experimental value:

[tex]\[ 2.85 \, \text{g/cm}^3 - 2.70 \, \text{g/cm}^3 = 0.15 \, \text{g/cm}^3 \][/tex]

5. Divide the difference by the accepted value:

[tex]\[ \frac{0.15 \, \text{g/cm}^3}{2.70 \, \text{g/cm}^3} = 0.0555555555555556 \][/tex]

6. Convert the fraction to a percentage by multiplying by 100:

[tex]\[ 0.0555555555555556 \times 100 = 5.55555555555556 \][/tex]

7. Round to the appropriate significant figures:

Both the measurements given (2.85 and 2.70) have three significant figures. Therefore, the percent error should also be reported with three significant figures.

[tex]\[ \text{Percent Error} \approx 5.56\% \][/tex]

So the student's percent error is approximately [tex]\( 5.56\% \)[/tex].