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A community athletic club holds an election to select a president and vice president. The nominations for selection include 4 females and 3 males.

What is the probability that a female is elected president and a male is elected vice president?

A. [tex]\frac{1}{12}[/tex]
B. [tex]\frac{12}{49}[/tex]
C. [tex]\frac{2}{7}[/tex]
D. [tex]\frac{7}{12}[/tex]


Sagot :

Let's solve the problem step by step.

1. Total Number of Candidates

There are 4 females and 3 males, summing up to:
[tex]\[ \text{Total candidates} = 4 + 3 = 7 \][/tex]

2. Probability of Electing a Female President

The probability of electing a female president is given by the number of females divided by the total number of candidates:
[tex]\[ P(\text{Female President}) = \frac{\text{Number of females}}{\text{Total candidates}} = \frac{4}{7} \approx 0.5714 \][/tex]

3. Remaining Candidates After Electing Female President

After a female is elected president, there are 6 candidates left (4 + 3 - 1):
[tex]\[ \text{Remaining candidates} = 7 - 1 = 6 \][/tex]

4. Probability of Electing a Male Vice President Given a Female President

There are still 3 males left out of the remaining 6 candidates. Thus, the probability of electing a male vice president given that a female president has been elected is:
[tex]\[ P(\text{Male Vice President} | \text{Female President}) = \frac{\text{Number of males}}{\text{Remaining candidates}} = \frac{3}{6} = 0.5 \][/tex]

5. Combined Probability of Electing a Female President and a Male Vice President

To find the combined probability of both events happening, we multiply the probabilities of the two independent events:
[tex]\[ P(\text{Female President and Male Vice President}) = P(\text{Female President}) \times P(\text{Male Vice President} | \text{Female President}) = \frac{4}{7} \times \frac{3}{6} = \frac{4}{7} \times 0.5 = \frac{2}{7} \approx 0.2857 \][/tex]

Hence, the correct answer is:
[tex]\[ \boxed{\frac{2}{7}} \][/tex]
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