Answer:
In order to cancel the fraction next to p, both sides must be multiplied by the reciprocal, instead of adding the positive version of the fraction to both sides.
Step-by-step explanation:
The error in this problem is the addition of 2/3 on both sides of the equation, which the solver thinks can be used to cancel the negative 2/3 next to the variable. The mistake is that the solver believes that the -2/3 is being added to the variable p, instead of being multiplied with it. This notation misunderstanding is evident in the solver's final answer, where 4 and 2/3 are placed next to each other as if it were equal to them being added.
The correction to this problem is to multiply both sides by the reciprocal of the fraction next to p, which can be shown algebraically:
[tex]-\frac{2}{3} p=4\\-\frac{2}{3} p(-\frac{3}{2} )=4(-\frac{3}{2} )\\\p=\frac{-12}{2} =-6[/tex]
