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19. Temperatures expressed in the Kelvin scale are higher than temperatures in the Celsius scale.

A. [tex]$460^{\circ}$[/tex]
B. [tex]$283^{\circ}$[/tex]
C. [tex]$273^{\circ}$[/tex]
D. [tex]$200^{\circ}$[/tex]

Sagot :

GinnyAnsweridn
To solve this problem, we need to convert each temperature from Kelvin to Celsius. The relationship between Kelvin and Celsius is given by the formula:

[tex]\[ C = K - 273.15 \][/tex]

where [tex]\( C \)[/tex] represents the temperature in Celsius and [tex]\( K \)[/tex] represents the temperature in Kelvin.

Let's convert each of the given options:

A. [tex]\( 460^\circ \)[/tex] K:

[tex]\[ C = 460 - 273.15 = 186.85^\circ \][/tex]

B. [tex]\( 283^\circ \)[/tex] K:

[tex]\[ C = 283 - 273.15 = 9.85^\circ \][/tex]

C. [tex]\( 273^\circ \)[/tex] K:

[tex]\[ C = 273 - 273.15 = -0.15^\circ \][/tex]

D. [tex]\( 200^\circ \)[/tex] K:

[tex]\[ C = 200 - 273.15 = -73.15^\circ \][/tex]

Therefore, the temperatures expressed in Kelvin converted to Celsius are as follows:

A. [tex]\( 460^\circ \)[/tex] K = [tex]\( 186.85^\circ \)[/tex] C

B. [tex]\( 283^\circ \)[/tex] K = [tex]\( 9.85^\circ \)[/tex] C

C. [tex]\( 273^\circ \)[/tex] K = [tex]\( -0.15^\circ \)[/tex] C

D. [tex]\( 200^\circ \)[/tex] K = [tex]\( -73.15^\circ \)[/tex] C
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