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[tex]\[\begin{array}{l}
g(t) = 2t + 1 \\
h(t) = 3t + 3 \\
\text{Find } g(5) \cdot h(5)
\end{array}\][/tex]

Sagot :

GinnyAnsweridn
Sure, let's solve this step-by-step.

Step 1: Define the functions [tex]\( g(t) \)[/tex] and [tex]\( h(t) \)[/tex].

Given:
[tex]\[ g(t) = 2t + 1 \][/tex]
[tex]\[ h(t) = 3t + 3 \][/tex]

Step 2: Evaluate [tex]\( g(t) \)[/tex] at [tex]\( t = 5 \)[/tex].

[tex]\[ g(5) = 2(5) + 1 \][/tex]
[tex]\[ g(5) = 10 + 1 \][/tex]
[tex]\[ g(5) = 11 \][/tex]

Step 3: Evaluate [tex]\( h(t) \)[/tex] at [tex]\( t = 5 \)[/tex].

[tex]\[ h(5) = 3(5) + 3 \][/tex]
[tex]\[ h(5) = 15 + 3 \][/tex]
[tex]\[ h(5) = 18 \][/tex]

Step 4: Calculate [tex]\( g(5) \cdot h(5) \)[/tex].

[tex]\[ g(5) \cdot h(5) = 11 \cdot 18 \][/tex]
[tex]\[ g(5) \cdot h(5) = 198 \][/tex]

Final Answer:
[tex]\[ g(5) = 11 \][/tex]
[tex]\[ h(5) = 18 \][/tex]
[tex]\[ g(5) \cdot h(5) = 198 \][/tex]
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