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Which choice is equivalent to the quotient shown here for acceptable values of [tex]x[/tex]?

[tex]\[ \sqrt{30(x-1)} \div \sqrt{5(x-1)^2} \][/tex]

A. [tex]\sqrt{150(x-1)^3}[/tex]

B. [tex]\sqrt{6(x-1)}[/tex]

C. [tex]\sqrt{30(x-1)-5(x-1)^2}[/tex]

D. [tex]\sqrt{\frac{6}{(x-1)}}[/tex]


Sagot :

To determine which choice is equivalent to the quotient [tex]\(\sqrt{30(x-1)} \div \sqrt{5(x-1)^2}\)[/tex] for acceptable values of [tex]\(x\)[/tex], we'll simplify the expression step by step.

First, let's rewrite the given quotient using division of square roots:

[tex]\[ \frac{\sqrt{30(x-1)}}{\sqrt{5(x-1)^2}} \][/tex]

Next, use the property of square roots to combine the numerator and denominator:

[tex]\[ \sqrt{\frac{30(x-1)}{5(x-1)^2}} \][/tex]

Now, simplify the expression under the square root:

[tex]\[ \sqrt{\frac{30(x-1)}{5(x-1)^2}} = \sqrt{\frac{30}{5} \cdot \frac{(x-1)}{(x-1)^2}} \][/tex]

Simplify the constants and the powers of [tex]\(x-1\)[/tex]:

[tex]\[ \sqrt{6 \cdot \frac{1}{x-1}} = \sqrt{\frac{6}{x-1}} \][/tex]

Thus, the simplified form of the given quotient is:

[tex]\[ \sqrt{\frac{6}{x-1}} \][/tex]

Finally, compare this result with the given choices:
- A. [tex]\(\sqrt{150(x-1)^3}\)[/tex]
- B. [tex]\(\sqrt{6(x-1)}\)[/tex]
- C. [tex]\(\sqrt{30(x-1) - 5(x-1)^2}\)[/tex]
- D. [tex]\(\sqrt{\frac{6}{(x-1)}}\)[/tex]

The correct answer is:
D. [tex]\(\sqrt{\frac{6}{(x-1)}}\)[/tex]