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What are the coordinates of the point that is [tex]\frac{3}{8}[/tex] of the way from [tex]A(-8,-9)[/tex] to [tex]B(24,-1)[/tex]?

A. [tex](4,-6)[/tex]
B. [tex](-6,4)[/tex]
C. [tex](-2,4)[/tex]
D. [tex](12,-4)[/tex]


Sagot :

To find the coordinates of the point that is [tex]\(\frac{3}{8}\)[/tex] of the way from point [tex]\(A(-8,-9)\)[/tex] to point [tex]\(B(24,-1)\)[/tex], we can use the section formula. The section formula helps us determine the coordinates of a point that divides a line segment into a particular ratio.

Given points [tex]\(A(x_1, y_1) = (-8, -9)\)[/tex] and [tex]\(B(x_2, y_2) = (24, -1)\)[/tex], and given that the fraction [tex]\(\frac{3}{8}\)[/tex] represents the part of the way from [tex]\(A\)[/tex] to [tex]\(B\)[/tex], we can find the coordinates [tex]\((x, y)\)[/tex] of the desired point as follows:

1. Calculate the total difference in the x-coordinates, [tex]\(x_2 - x_1\)[/tex], and the y-coordinates, [tex]\(y_2 - y_1\)[/tex]:
[tex]\[ x_2 - x_1 = 24 - (-8) = 24 + 8 = 32 \][/tex]
[tex]\[ y_2 - y_1 = -1 - (-9) = -1 + 9 = 8 \][/tex]

2. Multiply these differences by the given fraction [tex]\(\frac{3}{8}\)[/tex] to find the distances along the x-axis and y-axis from [tex]\(A\)[/tex] to the point:
[tex]\[ \text{x-distance} = \frac{3}{8} \times 32 = \frac{96}{8} = 12 \][/tex]
[tex]\[ \text{y-distance} = \frac{3}{8} \times 8 = \frac{24}{8} = 3 \][/tex]

3. Add these distances to the coordinates of [tex]\(A\)[/tex] to get the coordinates of the new point:
[tex]\[ x = x_1 + \text{x-distance} = -8 + 12 = 4 \][/tex]
[tex]\[ y = y_1 + \text{y-distance} = -9 + 3 = -6 \][/tex]

So, the coordinates of the point that is [tex]\(\frac{3}{8}\)[/tex] of the way from [tex]\(A(-8,-9)\)[/tex] to [tex]\(B(24,-1)\)[/tex] are [tex]\((4, -6)\)[/tex].

Thus, the correct answer is:
A. [tex]\((4, -6)\)[/tex]
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