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Sagot :
To solve the equation
[tex]\[ \frac{3y - 1}{2y + 4} = \frac{4}{5} \][/tex]
we need to clear the fractions by cross-multiplying. This means we will multiply both sides of the equation by [tex]\(5(2y + 4)\)[/tex]:
[tex]\[ 5(3y - 1) = 4(2y + 4) \][/tex]
Next, we distribute on both sides of the equation:
[tex]\[ 15y - 5 = 8y + 16 \][/tex]
Now, we need to isolate [tex]\(y\)[/tex]. We do this by first getting all the [tex]\(y\)[/tex]-terms on one side and the constants on the other side. Subtract [tex]\(8y\)[/tex] from both sides:
[tex]\[ 15y - 8y - 5 = 16 \][/tex]
This simplifies to:
[tex]\[ 7y - 5 = 16 \][/tex]
Next, we add 5 to both sides to isolate the term with [tex]\(y\)[/tex]:
[tex]\[ 7y = 21 \][/tex]
Now, divide both sides by 7 to solve for [tex]\(y\)[/tex]:
[tex]\[ y = 3 \][/tex]
Thus, the solution to the equation is:
[tex]\[ y = 3 \][/tex]
Therefore, the correct answer is:
[tex]\[ \boxed{y = 3} \][/tex]
Looking at the multiple-choice options provided:
A. [tex]\(y = 1 \frac{4}{7}\)[/tex]
B. [tex]\(y = 2 \frac{1}{2}\)[/tex]
C. [tex]\(y = 3\)[/tex]
D. [tex]\(y = 8\)[/tex]
The correct option is C. [tex]\(y = 3\)[/tex].
[tex]\[ \frac{3y - 1}{2y + 4} = \frac{4}{5} \][/tex]
we need to clear the fractions by cross-multiplying. This means we will multiply both sides of the equation by [tex]\(5(2y + 4)\)[/tex]:
[tex]\[ 5(3y - 1) = 4(2y + 4) \][/tex]
Next, we distribute on both sides of the equation:
[tex]\[ 15y - 5 = 8y + 16 \][/tex]
Now, we need to isolate [tex]\(y\)[/tex]. We do this by first getting all the [tex]\(y\)[/tex]-terms on one side and the constants on the other side. Subtract [tex]\(8y\)[/tex] from both sides:
[tex]\[ 15y - 8y - 5 = 16 \][/tex]
This simplifies to:
[tex]\[ 7y - 5 = 16 \][/tex]
Next, we add 5 to both sides to isolate the term with [tex]\(y\)[/tex]:
[tex]\[ 7y = 21 \][/tex]
Now, divide both sides by 7 to solve for [tex]\(y\)[/tex]:
[tex]\[ y = 3 \][/tex]
Thus, the solution to the equation is:
[tex]\[ y = 3 \][/tex]
Therefore, the correct answer is:
[tex]\[ \boxed{y = 3} \][/tex]
Looking at the multiple-choice options provided:
A. [tex]\(y = 1 \frac{4}{7}\)[/tex]
B. [tex]\(y = 2 \frac{1}{2}\)[/tex]
C. [tex]\(y = 3\)[/tex]
D. [tex]\(y = 8\)[/tex]
The correct option is C. [tex]\(y = 3\)[/tex].
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