IDNLearn.com: Your one-stop destination for finding reliable answers. Find reliable solutions to your questions quickly and easily with help from our experienced experts.
Sagot :
Sure, let's solve the quadratic equation [tex]\( x^2 - 4x - 21 = 0 \)[/tex] step by step.
### Step 1: Identify coefficients
For the quadratic equation of the form [tex]\( ax^2 + bx + c = 0 \)[/tex], the coefficients are:
- [tex]\(a = 1\)[/tex]
- [tex]\(b = -4\)[/tex]
- [tex]\(c = -21\)[/tex]
### Step 2: Calculate the discriminant
The discriminant [tex]\( \Delta \)[/tex] of a quadratic equation [tex]\( ax^2 + bx + c = 0 \)[/tex] is given by:
[tex]\[ \Delta = b^2 - 4ac \][/tex]
Plugging in the values of [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex]:
[tex]\[ \Delta = (-4)^2 - 4 \cdot 1 \cdot (-21) \][/tex]
Simplify the calculation:
[tex]\[ \Delta = 16 + 84 = 100 \][/tex]
So, the discriminant is [tex]\( \Delta = 100 \)[/tex].
### Step 3: Determine the number of roots
- If [tex]\( \Delta > 0 \)[/tex], the quadratic equation has 2 distinct real roots.
- If [tex]\( \Delta = 0 \)[/tex], there is exactly 1 real root (a repeated root).
- If [tex]\( \Delta < 0 \)[/tex], there are no real roots (the roots are complex).
Since [tex]\( \Delta = 100 \)[/tex] which is greater than 0, the quadratic equation has 2 distinct real roots.
### Step 4: Solve the quadratic equation
The roots of the quadratic equation can be found using the quadratic formula:
[tex]\[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \][/tex]
Substitute [tex]\(b = -4\)[/tex], [tex]\(a = 1\)[/tex], and [tex]\(\Delta = 100\)[/tex] into the formula:
[tex]\[ x = \frac{-(-4) \pm \sqrt{100}}{2 \cdot 1} = \frac{4 \pm 10}{2} \][/tex]
### Step 5: Simplify to find the roots
There are two solutions based on the [tex]\(\pm\)[/tex] sign:
1. For the [tex]\(+\)[/tex] case:
[tex]\[ x_1 = \frac{4 + 10}{2} = \frac{14}{2} = 7.0 \][/tex]
2. For the [tex]\(-\)[/tex] case:
[tex]\[ x_2 = \frac{4 - 10}{2} = \frac{-6}{2} = -3.0 \][/tex]
### Final Result
The discriminant is [tex]\(100\)[/tex], indicating that there are 2 distinct real roots. The solutions to the quadratic equation [tex]\( x^2 - 4x - 21 = 0 \)[/tex] are:
[tex]\[ x_1 = 7.0 \quad \text{and} \quad x_2 = -3.0 \][/tex]
Thus, the result is:
[tex]\[ (100, 2, 7.0, -3.0) \][/tex]
### Step 1: Identify coefficients
For the quadratic equation of the form [tex]\( ax^2 + bx + c = 0 \)[/tex], the coefficients are:
- [tex]\(a = 1\)[/tex]
- [tex]\(b = -4\)[/tex]
- [tex]\(c = -21\)[/tex]
### Step 2: Calculate the discriminant
The discriminant [tex]\( \Delta \)[/tex] of a quadratic equation [tex]\( ax^2 + bx + c = 0 \)[/tex] is given by:
[tex]\[ \Delta = b^2 - 4ac \][/tex]
Plugging in the values of [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex]:
[tex]\[ \Delta = (-4)^2 - 4 \cdot 1 \cdot (-21) \][/tex]
Simplify the calculation:
[tex]\[ \Delta = 16 + 84 = 100 \][/tex]
So, the discriminant is [tex]\( \Delta = 100 \)[/tex].
### Step 3: Determine the number of roots
- If [tex]\( \Delta > 0 \)[/tex], the quadratic equation has 2 distinct real roots.
- If [tex]\( \Delta = 0 \)[/tex], there is exactly 1 real root (a repeated root).
- If [tex]\( \Delta < 0 \)[/tex], there are no real roots (the roots are complex).
Since [tex]\( \Delta = 100 \)[/tex] which is greater than 0, the quadratic equation has 2 distinct real roots.
### Step 4: Solve the quadratic equation
The roots of the quadratic equation can be found using the quadratic formula:
[tex]\[ x = \frac{-b \pm \sqrt{\Delta}}{2a} \][/tex]
Substitute [tex]\(b = -4\)[/tex], [tex]\(a = 1\)[/tex], and [tex]\(\Delta = 100\)[/tex] into the formula:
[tex]\[ x = \frac{-(-4) \pm \sqrt{100}}{2 \cdot 1} = \frac{4 \pm 10}{2} \][/tex]
### Step 5: Simplify to find the roots
There are two solutions based on the [tex]\(\pm\)[/tex] sign:
1. For the [tex]\(+\)[/tex] case:
[tex]\[ x_1 = \frac{4 + 10}{2} = \frac{14}{2} = 7.0 \][/tex]
2. For the [tex]\(-\)[/tex] case:
[tex]\[ x_2 = \frac{4 - 10}{2} = \frac{-6}{2} = -3.0 \][/tex]
### Final Result
The discriminant is [tex]\(100\)[/tex], indicating that there are 2 distinct real roots. The solutions to the quadratic equation [tex]\( x^2 - 4x - 21 = 0 \)[/tex] are:
[tex]\[ x_1 = 7.0 \quad \text{and} \quad x_2 = -3.0 \][/tex]
Thus, the result is:
[tex]\[ (100, 2, 7.0, -3.0) \][/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is committed to your satisfaction. Thank you for visiting, and see you next time for more helpful answers.