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To determine the average rate of change in attendance from Year 2 to Year 5, we will follow these steps:
1. Identify the attendance values for the specified years:
- Year 2 attendance: 298.3 thousand people.
- Year 5 attendance: 333.7 thousand people.
2. Determine the time interval:
- The number of years between Year 2 and Year 5 is [tex]\( 5 - 2 = 3 \)[/tex] years.
3. Calculate the difference in attendance between Year 5 and Year 2:
- Change in attendance = [tex]\( 333.7 - 298.3 = 35.4 \)[/tex] thousand people.
4. Calculate the average rate of change:
- Average rate of change in attendance per year = [tex]\( \frac{\text{Change in attendance}}{\text{Number of years}} \)[/tex]
- Average rate of change = [tex]\( \frac{35.4 \text{ thousand people}}{3 \text{ years}} = 11.8 \text{ thousand people per year} \)[/tex].
Given these calculations, the average rate of change in attendance from Year 2 to Year 5 is 11,800 people increased per year. The correct answer is:
Attendance increased by an average of 11,800 people per year from Year 2 to Year 5.
1. Identify the attendance values for the specified years:
- Year 2 attendance: 298.3 thousand people.
- Year 5 attendance: 333.7 thousand people.
2. Determine the time interval:
- The number of years between Year 2 and Year 5 is [tex]\( 5 - 2 = 3 \)[/tex] years.
3. Calculate the difference in attendance between Year 5 and Year 2:
- Change in attendance = [tex]\( 333.7 - 298.3 = 35.4 \)[/tex] thousand people.
4. Calculate the average rate of change:
- Average rate of change in attendance per year = [tex]\( \frac{\text{Change in attendance}}{\text{Number of years}} \)[/tex]
- Average rate of change = [tex]\( \frac{35.4 \text{ thousand people}}{3 \text{ years}} = 11.8 \text{ thousand people per year} \)[/tex].
Given these calculations, the average rate of change in attendance from Year 2 to Year 5 is 11,800 people increased per year. The correct answer is:
Attendance increased by an average of 11,800 people per year from Year 2 to Year 5.
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