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The table shows the ages of people attending three different movies in a movie theater.

\begin{tabular}{|c|c|c|c|}
\hline
& Under 20 & Between 20 and [tex]$40$[/tex] & Over 40 \\
\hline
Action & 8 & 5 & 12 \\
\hline
Comedy & 16 & 11 & 1 \\
\hline
Drama & 10 & 15 & 9 \\
\hline
\end{tabular}

The manager is going to randomly select one person to win a free movie pass. What is the probability that the person selected is watching the drama movie? Round the answer to the nearest hundredth. Enter the answer in the box.

[tex]$\square$[/tex]


Sagot :

First, we need to determine the total number of people attending the movies. We will add up all the attendees for each type of movie.

For the Action movie:
- Under 20: 8
- Between 20 and 40: 5
- Over 40: 12

Total for Action = 8 + 5 + 12 = 25

For the Comedy movie:
- Under 20: 16
- Between 20 and 40: 11
- Over 40: 1

Total for Comedy = 16 + 11 + 1 = 28

For the Drama movie:
- Under 20: 10
- Between 20 and 40: 15
- Over 40: 9

Total for Drama = 10 + 15 + 9 = 34

Next, we calculate the total number of people attending any type of movie:
- Total people = Total for Action + Total for Comedy + Total for Drama
- Total people = 25 + 28 + 34 = 87

Now, we need to calculate the probability that a randomly selected person is watching the Drama movie. This probability is found by dividing the number of people watching Drama by the total number of people:

[tex]\[ \text{Probability of selecting a person watching Drama} = \frac{\text{Number watching Drama}}{\text{Total number of people}} = \frac{34}{87} \][/tex]

Converting this fraction into a decimal:

[tex]\[ \frac{34}{87} \approx 0.39080459770114945 \][/tex]

Finally, we round this value to the nearest hundredth:

[tex]\[ 0.39080459770114945 \approx 0.39 \][/tex]

So, the probability that the person selected is watching the Drama movie, rounded to the nearest hundredth, is [tex]\(0.39\)[/tex].