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Which of the following equations represents a line that passes through the points [tex]$(4,-6)$[/tex] and [tex]$(0,-4)$[/tex]?

I. [tex][tex]$x+2y=-6$[/tex][/tex]

II. [tex]$y-1=-\frac{1}{2}(x+10)$[/tex]

A. Neither
B. I only
C. II only
D. I and II


Sagot :

To determine which of the given equations represents a line passing through the points [tex]\((4, -6)\)[/tex] and [tex]\((0, -4)\)[/tex], we need to check if both points satisfy each equation.

Let’s examine the given equations:

### Equation I: [tex]\( x + 2y = -6 \)[/tex]

1. Substituting [tex]\((4, -6)\)[/tex]:
[tex]\[ 4 + 2(-6) = 4 - 12 = -8 \][/tex]
This simplifies to [tex]\(-8 \neq -6\)[/tex], so [tex]\((4, -6)\)[/tex] does not satisfy this equation.

2. Substituting [tex]\((0, -4)\)[/tex]:
[tex]\[ 0 + 2(-4) = 0 - 8 = -8 \][/tex]
This simplifies to [tex]\(-8 \neq -6\)[/tex], so [tex]\((0, -4)\)[/tex] also does not satisfy this equation.

Since neither point satisfies Equation I, this equation does not represent the line passing through the points [tex]\((4, -6)\)[/tex] and [tex]\((0, -4)\)[/tex].

### Equation II: [tex]\( y - 1 = -\frac{1}{2}(x + 10) \)[/tex]

1. Substituting [tex]\((4, -6)\)[/tex]:
[tex]\[ -6 - 1 = -\frac{1}{2}(4 + 10) \][/tex]
Simplifying the right side:
[tex]\[ -6 - 1 = -\frac{1}{2} \times 14 = -7 \][/tex]
This equation simplifies to [tex]\(-7 = -7\)[/tex], so [tex]\((4, -6)\)[/tex] satisfies Equation II.

2. Substituting [tex]\((0, -4)\)[/tex]:
[tex]\[ -4 - 1 = -\frac{1}{2}(0 + 10) \][/tex]
Simplifying the right side:
[tex]\[ -4 - 1 = -\frac{1}{2} \times 10 = -5 \][/tex]
This equation simplifies to [tex]\(-5 = -5\)[/tex], so [tex]\((0, -4)\)[/tex] also satisfies Equation II.

Since both points satisfy Equation II, this equation does represent the line passing through the points [tex]\((4, -6)\)[/tex] and [tex]\((0, -4)\)[/tex].

### Conclusion:

The equation that represents the line passing through the points [tex]\((4, -6)\)[/tex] and [tex]\((0, -4)\)[/tex] is
[tex]\[ \text{II only} \][/tex]