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Sagot :
To determine which, if any, of the regions in an animal reservation have a population density less than 60 animals per square mile, we need to calculate the population density for each region. The population density is calculated by the formula:
[tex]\[ \text{Population Density} = \frac{\text{Number of Animals}}{\text{Area (in square miles)}} \][/tex]
From the table, the number of animals in each region and the area (4 square miles) are given as follows:
- Region A: 42,500 animals
- Region B: 60,800 animals
- Region C: 57,300 animals
- Region D: 49,200 animals
The area for all regions is 4 square miles.
Let's calculate the population density for each region:
1. Region A:
[tex]\[ \text{Population Density} = \frac{42,500}{4} = 10,625 \text{ animals per square mile} \][/tex]
2. Region B:
[tex]\[ \text{Population Density} = \frac{60,800}{4} = 15,200 \text{ animals per square mile} \][/tex]
3. Region C:
[tex]\[ \text{Population Density} = \frac{57,300}{4} = 14,325 \text{ animals per square mile} \][/tex]
4. Region D:
[tex]\[ \text{Population Density} = \frac{49,200}{4} = 12,300 \text{ animals per square mile} \][/tex]
Now, let's determine if any of these population densities are less than 60 animals per square mile:
- Region A: 10,625 animals per square mile
- Region B: 15,200 animals per square mile
- Region C: 14,325 animals per square mile
- Region D: 12,300 animals per square mile
From the calculations, it is clear that none of the regions have a population density less than 60 animals per square mile.
Therefore, the correct answer is:
None of the regions have a population density less than 60 animals per square mile.
[tex]\[ \text{Population Density} = \frac{\text{Number of Animals}}{\text{Area (in square miles)}} \][/tex]
From the table, the number of animals in each region and the area (4 square miles) are given as follows:
- Region A: 42,500 animals
- Region B: 60,800 animals
- Region C: 57,300 animals
- Region D: 49,200 animals
The area for all regions is 4 square miles.
Let's calculate the population density for each region:
1. Region A:
[tex]\[ \text{Population Density} = \frac{42,500}{4} = 10,625 \text{ animals per square mile} \][/tex]
2. Region B:
[tex]\[ \text{Population Density} = \frac{60,800}{4} = 15,200 \text{ animals per square mile} \][/tex]
3. Region C:
[tex]\[ \text{Population Density} = \frac{57,300}{4} = 14,325 \text{ animals per square mile} \][/tex]
4. Region D:
[tex]\[ \text{Population Density} = \frac{49,200}{4} = 12,300 \text{ animals per square mile} \][/tex]
Now, let's determine if any of these population densities are less than 60 animals per square mile:
- Region A: 10,625 animals per square mile
- Region B: 15,200 animals per square mile
- Region C: 14,325 animals per square mile
- Region D: 12,300 animals per square mile
From the calculations, it is clear that none of the regions have a population density less than 60 animals per square mile.
Therefore, the correct answer is:
None of the regions have a population density less than 60 animals per square mile.
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