Find the best solutions to your problems with the help of IDNLearn.com's experts. Discover in-depth answers to your questions from our community of experienced professionals.
Sagot :
Certainly! Let's go through the calculation step by step, given the values [tex]\( a = 3 \)[/tex], [tex]\( b = -4 \)[/tex], and [tex]\( c = 8 \)[/tex].
We need to evaluate the expression:
[tex]\[ \frac{a \cdot b^2}{c + 12} \][/tex]
1. Square the value of [tex]\( b \)[/tex]:
Given [tex]\( b = -4 \)[/tex]:
[tex]\[ b^2 = (-4)^2 = 16 \][/tex]
2. Multiply [tex]\( a \)[/tex] by [tex]\( b^2 \)[/tex]:
Given [tex]\( a = 3 \)[/tex] and from step 1, [tex]\( b^2 = 16 \)[/tex]:
[tex]\[ a \cdot b^2 = 3 \cdot 16 = 48 \][/tex]
3. Add 12 to [tex]\( c \)[/tex]:
Given [tex]\( c = 8 \)[/tex]:
[tex]\[ c + 12 = 8 + 12 = 20 \][/tex]
4. Divide the product from step 2 by the sum from step 3:
From step 2, we have [tex]\( a \cdot b^2 = 48 \)[/tex] and from step 3, [tex]\( c + 12 = 20 \)[/tex]:
[tex]\[ \frac{a \cdot b^2}{c + 12} = \frac{48}{20} = 2.4 \][/tex]
So, the evaluated expression is:
[tex]\[ \boxed{2.4} \][/tex]
We need to evaluate the expression:
[tex]\[ \frac{a \cdot b^2}{c + 12} \][/tex]
1. Square the value of [tex]\( b \)[/tex]:
Given [tex]\( b = -4 \)[/tex]:
[tex]\[ b^2 = (-4)^2 = 16 \][/tex]
2. Multiply [tex]\( a \)[/tex] by [tex]\( b^2 \)[/tex]:
Given [tex]\( a = 3 \)[/tex] and from step 1, [tex]\( b^2 = 16 \)[/tex]:
[tex]\[ a \cdot b^2 = 3 \cdot 16 = 48 \][/tex]
3. Add 12 to [tex]\( c \)[/tex]:
Given [tex]\( c = 8 \)[/tex]:
[tex]\[ c + 12 = 8 + 12 = 20 \][/tex]
4. Divide the product from step 2 by the sum from step 3:
From step 2, we have [tex]\( a \cdot b^2 = 48 \)[/tex] and from step 3, [tex]\( c + 12 = 20 \)[/tex]:
[tex]\[ \frac{a \cdot b^2}{c + 12} = \frac{48}{20} = 2.4 \][/tex]
So, the evaluated expression is:
[tex]\[ \boxed{2.4} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.