Join the IDNLearn.com community and start finding the answers you need today. Ask any question and receive comprehensive, well-informed responses from our dedicated team of experts.
Sagot :
To find the expression equivalent to [tex]\((p - q)(x)\)[/tex], we need to calculate [tex]\(p(x) - q(x)\)[/tex].
First, let's rewrite the given functions for clarity:
[tex]\[ p(x) = x^2 - 1 \][/tex]
[tex]\[ q(x) = 5(x - 1) \][/tex]
Now, we will calculate [tex]\(p(x) - q(x)\)[/tex]:
[tex]\[ (p - q)(x) = p(x) - q(x) \][/tex]
Substitute the functions [tex]\(p(x)\)[/tex] and [tex]\(q(x)\)[/tex]:
[tex]\[ (p - q)(x) = (x^2 - 1) - 5(x - 1) \][/tex]
Next, simplify the expression:
[tex]\[ (p - q)(x) = (x^2 - 1) - 5x + 5 \][/tex]
Combining like terms, we get:
[tex]\[ (p - q)(x) = x^2 - 1 - 5x + 5 \][/tex]
[tex]\[ (p - q)(x) = x^2 - 5x - 1 + 5 \][/tex]
[tex]\[ (p - q)(x) = x^2 - 5x + 4 \][/tex]
Therefore, the correct expression equivalent to [tex]\((p - q)(x)\)[/tex] is:
[tex]\[ \left(x^2 - 1\right) - 5(x - 1) \][/tex]
This matches the third option in the list provided:
[tex]\[ \left(x^2 - 1\right) - 5(x - 1) \][/tex]
First, let's rewrite the given functions for clarity:
[tex]\[ p(x) = x^2 - 1 \][/tex]
[tex]\[ q(x) = 5(x - 1) \][/tex]
Now, we will calculate [tex]\(p(x) - q(x)\)[/tex]:
[tex]\[ (p - q)(x) = p(x) - q(x) \][/tex]
Substitute the functions [tex]\(p(x)\)[/tex] and [tex]\(q(x)\)[/tex]:
[tex]\[ (p - q)(x) = (x^2 - 1) - 5(x - 1) \][/tex]
Next, simplify the expression:
[tex]\[ (p - q)(x) = (x^2 - 1) - 5x + 5 \][/tex]
Combining like terms, we get:
[tex]\[ (p - q)(x) = x^2 - 1 - 5x + 5 \][/tex]
[tex]\[ (p - q)(x) = x^2 - 5x - 1 + 5 \][/tex]
[tex]\[ (p - q)(x) = x^2 - 5x + 4 \][/tex]
Therefore, the correct expression equivalent to [tex]\((p - q)(x)\)[/tex] is:
[tex]\[ \left(x^2 - 1\right) - 5(x - 1) \][/tex]
This matches the third option in the list provided:
[tex]\[ \left(x^2 - 1\right) - 5(x - 1) \][/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.