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Sagot :
Sure, let's solve this problem step by step.
1. Identify the given values:
- Density of ethanol, [tex]\( d = 0.789 \, \text{g/mL} \)[/tex]
- Volume of ethanol, [tex]\( V = 150.0 \, \text{mL} \)[/tex]
2. Recall the formula for mass:
The mass can be found using the formula:
[tex]\[ \text{Mass} = \text{Density} \times \text{Volume} \][/tex]
3. Substitute the given values into the formula:
[tex]\[ \text{Mass} = 0.789 \, \text{g/mL} \times 150.0 \, \text{mL} \][/tex]
4. Perform the multiplication:
[tex]\[ \text{Mass} = 0.789 \times 150.0 = 118.35000000000001 \, \text{g} \][/tex]
Therefore, the mass of the ethanol sample is [tex]\( 118.35 \, \text{g} \)[/tex] (keeping the significant figures in mind).
1. Identify the given values:
- Density of ethanol, [tex]\( d = 0.789 \, \text{g/mL} \)[/tex]
- Volume of ethanol, [tex]\( V = 150.0 \, \text{mL} \)[/tex]
2. Recall the formula for mass:
The mass can be found using the formula:
[tex]\[ \text{Mass} = \text{Density} \times \text{Volume} \][/tex]
3. Substitute the given values into the formula:
[tex]\[ \text{Mass} = 0.789 \, \text{g/mL} \times 150.0 \, \text{mL} \][/tex]
4. Perform the multiplication:
[tex]\[ \text{Mass} = 0.789 \times 150.0 = 118.35000000000001 \, \text{g} \][/tex]
Therefore, the mass of the ethanol sample is [tex]\( 118.35 \, \text{g} \)[/tex] (keeping the significant figures in mind).
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