To solve the problem step-by-step, let's complete the statement according to the given solution.
First, we need to find the sum of 3 and -2:
[tex]\[ 3 + (-2) \][/tex]
When adding the numbers, we have:
[tex]\[ 3 + (-2) = 1 \][/tex]
Now, we need to determine how far 1 is from 3 on a number line.
The distance from 3 to 1 is:
[tex]\[ |3 - 1| = |2| = 2 \][/tex]
So, the number 1 is 2 units away from 3.
Next, we determine the direction from 3 to 1 on a number line:
- Since 1 is less than 3, the movement is in the negative direction.
Putting it all together, we get:
[tex]\[ 3 + (-2) \text{ is } 2 \text{ units from } 3 \text{, in the negative direction.} \][/tex]
Thus, the completed statement is:
[tex]\[ 3 + (-2) \text{ is } \boxed{2} \text{ units from 3, in the } \boxed{negative} \text{ direction.} \][/tex]
