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What are the solutions, if any, of the equation [tex]$(x+49)^2=24$[/tex]?

A. [tex]x= \pm \sqrt{73}[/tex]

B. [tex]x=-7 \pm 2 \sqrt{6}[/tex]

C. This equation has no real solutions.

D. [tex]x=-49 \pm 2 \sqrt{6}[/tex]


Sagot :

To solve the equation [tex]\((x + 49)^2 = 24\)[/tex], we need to isolate [tex]\(x\)[/tex]. Here's a step-by-step solution:

1. Start with the given equation:
[tex]\[ (x + 49)^2 = 24 \][/tex]

2. Take the square root of both sides to undo the square on the left-hand side. Remember, when taking the square root, you need to consider both the positive and the negative roots:
[tex]\[ x + 49 = \pm \sqrt{24} \][/tex]

3. Simplify the square root of 24. Note that [tex]\(\sqrt{24} = \sqrt{4 \times 6} = 2\sqrt{6}\)[/tex], so:
[tex]\[ x + 49 = \pm 2\sqrt{6} \][/tex]

4. Solve for [tex]\(x\)[/tex] by isolating it on one side of the equation:
[tex]\[ x = -49 \pm 2\sqrt{6} \][/tex]

Thus, the solutions to the equation [tex]\((x + 49)^2 = 24\)[/tex] are:
[tex]\[ x = -49 + 2\sqrt{6} \quad \text{and} \quad x = -49 - 2\sqrt{6} \][/tex]

This fits with the provided multiple-choice options, where the correct answer is:
[tex]\[ x=-49 \pm 2 \sqrt{6} \][/tex]
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