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What is the solution of this equation?

[tex]
\begin{array}{l}
-\frac{1}{2} n^2 + 18 = 0 \\
n = \pm \square
\end{array}
[tex]


Sagot :

To solve the equation [tex]\(-\frac{1}{2} n^2 + 18 = 0\)[/tex], follow these steps:

1. Rewrite the equation in standard quadratic form [tex]\(ax^2 + bx + c = 0\)[/tex]:
[tex]\[ -\frac{1}{2} n^2 + 18 = 0 \][/tex]

2. Move the constant term to the other side of the equation by subtracting 18 from both sides:
[tex]\[ -\frac{1}{2} n^2 = -18 \][/tex]

3. Multiply both sides by [tex]\(-2\)[/tex] to eliminate the fraction:
[tex]\[ n^2 = 36 \][/tex]

4. Take the square root of both sides to solve for [tex]\(n\)[/tex]:
[tex]\[ n = \pm \sqrt{36} \][/tex]

5. Simplify the square root:
[tex]\[ n = \pm 6 \][/tex]

So, the solution of the equation is:
[tex]\[ n = \pm 6 \][/tex]