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Carly tutors students in math on the weekends and offers both thirty-minute sessions and sixty-minute sessions. She earns [tex]\$15[/tex] for each thirty-minute session and [tex]\$25[/tex] for each sixty-minute session.

If she earned [tex]\$230[/tex] this past weekend and had [tex]x[/tex] thirty-minute sessions and [tex]x-2[/tex] sixty-minute sessions, what is the value of [tex]x[/tex]?

A. 5
B. 8
C. 6
D. 7


Sagot :

Let's solve the problem step by step to determine the number of thirty-minute sessions Carly had, denoted by [tex]\(x\)[/tex].

1. Understand the given information:
- Carly earns \[tex]$15 for each thirty-minute session. - Carly earns \$[/tex]25 for each sixty-minute session.
- She earned a total of \$230 over the weekend.
- The number of thirty-minute sessions is [tex]\(x\)[/tex].
- The number of sixty-minute sessions is [tex]\(x - 2\)[/tex].

2. Set up the equation:
- The total earnings from the thirty-minute sessions are [tex]\(15x\)[/tex] dollars.
- The total earnings from the sixty-minute sessions are [tex]\(25(x - 2)\)[/tex] dollars.
- The total earnings combine to give the equation:
[tex]\[ 15x + 25(x - 2) = 230 \][/tex]

3. Simplify the equation:
[tex]\[ 15x + 25(x - 2) = 230 \][/tex]
Distribute the 25 in the second term:
[tex]\[ 15x + 25x - 50 = 230 \][/tex]
Combine like terms:
[tex]\[ 40x - 50 = 230 \][/tex]

4. Solve for [tex]\(x\)[/tex]:
Add 50 to both sides of the equation to isolate the term with [tex]\(x\)[/tex]:
[tex]\[ 40x - 50 + 50 = 230 + 50 \][/tex]
[tex]\[ 40x = 280 \][/tex]
Divide both sides by 40 to solve for [tex]\(x\)[/tex]:
[tex]\[ x = \frac{280}{40} \][/tex]
[tex]\[ x = 7 \][/tex]

Therefore, Carly had [tex]\(7\)[/tex] thirty-minute sessions.

The correct answer is [tex]\( \boxed{7} \)[/tex].